The cubic unit cell this metal crystallize as is BCC structure .
<h3>
What is unit cell ?</h3>
The structure of a crystalline solid, whether a metal or not, is best described by considering its simplest repeating unit, which is referred to as its unit cell.
The unit cell consists of lattice points that represent the locations of atoms or ions.
The entire structure then consists of this unit cell repeating in three dimensions
n= 2
Hence our assumption was correct
It is a BCC structure .
Therefore the cubic unit cell this metal crystallize as is BCC structure .
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Answer: The value of the equilibrium constant Kc for this reaction is 3.72
Explanation:
Equilibrium concentration of 
= 
Equilibrium concentration of 
= 
Equilibrium concentration of 
= 
Equilibrium concentration of 
= 
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as 
For the given chemical reaction:
The expression for is written as:
![K_c=\frac{[NO_2]^3\times [H_2O]^1}{[HNO_3]^2\times [NO]^1}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BNO_2%5D%5E3%5Ctimes%20%5BH_2O%5D%5E1%7D%7B%5BHNO_3%5D%5E2%5Ctimes%20%5BNO%5D%5E1%7D)
Thus the value of the equilibrium constant Kc for this reaction is 3.72
Ionic bonds form when a nonmetal and a metal exchange electrons, while covalent bonds form when electrons are shared between two nonmetals. An ionic bond is a type of chemical bond formed through an electrostatic attraction between two oppositely charged ions.
Answer:
280 g
Explanation:
Let's consider the decomposition of ammonium nitrate.
NH₄NO₃(s) ⇒ N₂(g) + 0.5 O₂(g) + 2 H₂O(g)
We can establish the following relations:
- The molar mass of NH₄NO₃ is 80.04 g/mol.
- The molar ratio of NH₄NO₃ to N₂ is 1:1.
- The molar mass of N₂ is 28.01 g/mol.
The mass of N₂ produced when 800 g of NH₄NO₃ react is:
Answer:
20.25 W
Explanation:
Applying,
P = I²R.................... Equation 1
Where P = Power, I = current drawn by the test light, R = Resistance of the test light
From the question,
Given: I = 1.5 A, R = 9.00 Ω
Substitute these values into equation 1
P = (1.5²)(9)
P = 2.25×9
P = 20.25 W
