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Licemer1 [7]
3 years ago
5

Starting with 1.5052g of BaCl2•2H2O and excessH2SO4, how many grams of BaSO4 can be formed?

Chemistry
2 answers:
muminat3 years ago
6 0
1.5052g BaCl2.2H2O => 1.5052g / 274.25 g/mol = 0.0054884 mol
=> 0.0054884 mol Ba 
<span>This means that at most 0.0054884 mol BaSO4 can form since Ba is the limiting reagent. </span>
<span>0.0054884 mol BaSO4 => 0.0054884 mol * 233.39 g/mol = 1.2809 g BaSO4</span>
Anuta_ua [19.1K]3 years ago
3 0

<u>Answer:</u> The mass of barium sulfate produced is 1.45 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

Given mass of BaCl_2.2H_2O = 1.5052 g

Molar mass of BaCl_2.2H_2O = 244.26 g/mol

Putting values in equation 1, we get:

\text{Moles of }BaCl_2.2H_2O=\frac{1.5052g}{244.26g/mol}=0.0062mol

The chemical equation for the reaction of barium chloride and sulfuric acid follows:

BaCl_2.2H_2O+H_2SO_4\rightarrow BaSO_4+2HCl+2H_2O

As, sulfuric acid is present in excess, it is considered as an excess reagent.

Thus, BaCl_2.2H_2O is considered as a limiting reagent because it limits the formation of product

By Stoichiometry of the reaction:

1 mole of BaCl_2.2H_2O produces 1 mole of barium sulfate

So, 0.0062 moles of BaCl_2.2H_2O will produce = \frac{1}{1}\times 0.0062=0.0062 moles of barium sulfate

Now, calculating the mass of barium sulfate by using equation 1:

Molar mass of barium sulfate = 233.4 g/mol

Moles of barium sulfate = 0.0062 moles

Putting values in equation 1, we get:

0.0062mol=\frac{\text{Mass of barium sulfate}}{233.4g/mol}\\\\\text{Mass of barium sulfate}=(0.0062mol\times 233.4g/mol)=1.45g

Hence, the mass of barium sulfate produced is 1.45 grams.

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Consider the reaction given below.
Drupady [299]

Answer:

  • <u>K =  0.167 s⁻¹</u>

Explanation:

<u>1) Rate law, at a given temperature:</u>

  • Since all the data are obtained at the same temperature, the equilibrium constant is the same.

  • Since only reactants A and B participate in the reaction, you assume that the form of the rate law is:

        r = K [A]ᵃ [B]ᵇ

<u>2) Use the data from the table</u>

  • Since the first and second set of data have the same concentration of the reactant A, you can use them to find the exponent b:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₂ = (1.50)ᵃ (2.50)ᵇ = 2.50 × 10⁻¹ M/s

         Divide r₂ by r₁:     [ 2.50 / 1.50] ᵇ = 1 ⇒ b = 0

  • Use the first and second set of data to find the exponent a:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₃ = (3.00)ᵃ (1.50)ᵇ = 5.00 × 10⁻¹ M/s

        Divide r₃ by r₂: [3.00 / 1.50]ᵃ = [5.00 / 2.50]

                                  2ᵃ = 2 ⇒ a = 1

         

<u>3) Write the rate law</u>

  • r = K [A]¹ [B]⁰ = K[A]

This means, that the rate is independent of reactant B and is of first order respect reactant A.

<u>4) Use any set of data to find K</u>

With the first set of data

  • r = K (1.50 M) = 2.50 × 10⁻¹ M/s ⇒ K = 0.250 M/s / 1.50 M = 0.167 s⁻¹

Result: the rate constant is K =  0.167 s⁻¹

6 0
3 years ago
How can chemical weathering contribute to physical weathering?
lora16 [44]

A-leads to the abrasion of rocks and minerals

A-dense vegetation cover

True

Explanation:

Weathering is the physical disintegration and chemical decomposition of rocks to form sediments and soils.

Agent of weathering are wind, water and glacier.

Chemical weathering contributes to physical weathering in that it leads to the abrasion of rocks and minerals.

During chemical weathering, a rock chemically combines with materials in the environment and weakens it.

When physical weathering processes are induced, grains produced independently weakening of bonds in rocks grind against one another and wears each other off.

An area with a dense vegetation cover undergoes rapid chemical weathering:

  • Plant roots penetrates deep into the rock and increases the surface area of chemical action.
  • Plants produce chemicals that combines with rocks and causes them to decay.
  • Since the area is always moist, chemical action becomes more severe.

Buildings and statues made of stone are subjected to the same degree of weathering as rocks exposed naturally.

This is true.

Statues and buildings weather just like rocks we find in nature.

It is the same sunshine and rain that impacts rocks that also impacts buildings and statues.

So they degrade at the same rate except they are protected.

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5 0
3 years ago
WILL MARK BRAINLIEST!!!! PLS HELP!!!
docker41 [41]

True

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6 0
3 years ago
A chemist needs to determine the concentration of a sulfuric acid solution by titration with a standard sodium hydroxide solutio
brilliants [131]

Explanation:

The given data is as follows.

          Concentration of standard NaOH solution = 0.1922 M

Let the original acid solution concentration be x.

                        M_{1}V_{1} = M_{2}V_{2}

                        x \times 25 = 250 \times M_{2}

                         M_{2} = \frac{x \times 25}{250}

                                     = 0.1 x M

V_{2} = 10.00 mL (given)

The reaction equation is as follows.

             2NaOH + H_{2}SO_{4} \rightarrow Na_{2}SO_{4} + 2H_{2}O

   Concentration × Volume of H_{2}SO_{4} = Concentration × Volume of NaOH

           \frac{M_{2}V_{2}}{n_{2}} = \frac{M_{3}V_{3}}{n_{3}}

     \frac{0.1 x \times 10 ml}{1} = \frac{0.1922 M \times 13.68 ml}{2}

                  x = 1.314 M

Therefore, we can conclude that the concentration of the original sulfuric acid solution is 1.314 M.

7 0
3 years ago
Does anyone know how to do this???​
Lelechka [254]

Answer:

2.9 g/cm³

Explanation:

From the question given above, the following data were obtained:

Mass = 236.376 g

Volume = 81.5 cm³

Density =?

Density can be defined as the mass of a substance per unit volume of the substance. It can be expressed mathematically as:

Density = mass /volume

With the above formula, we can obtain the density of the object as shown below:

Mass = 236.376 g

Volume = 81.5 cm³

Density =?

Density = mass /volume

Density = 236.376 / 81.5

Density = 2.9 g/cm³

Thus, the density of the object is 2.9 g/cm³

8 0
3 years ago
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