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WITCHER [35]
3 years ago
8

A sample of N2 gas occupying 800.0 mL at 20.0°C is chilled on ice to 0.00°C. If the pressure also drops from 1.50 atm to

Chemistry
2 answers:
Marat540 [252]3 years ago
4 0

Answer:

Explanation:A sample of N2 gas occupying 800.0 mL at 20.0°C is chilled on ice to 0.00°C. If the pressure also drops from 1.50 atm to

1.20 atm, what is the final volume of the gas?

Which equation should you use

Studentka2010 [4]3 years ago
3 0

Answer:

We will use the combined gas equation.

The final volume V₂=931.74 mL

Explanation:

The combined gas equation shows the interrelationship between the volume, the pressure and the absolute temperature of a fixed mass of an ideal gas,

P₁V₁/T₁=P₂V₂/T₂

Because we are looking for the volume after the initial conditions havre been varied, we will call this volume, volume 2 ( V₂)

Let us make it the subject of the equation.

V₂=(P₁V₁T₂)T₁P₂

P₁=1.50 ATM

P₂=1.20 ATM

V₁=800 mL

V₂=?

T₁=(20+273)K=293 K

T₂=0+273 K=273 K

V₂=(1.50 ×800×273)/(293×1.2)

V₂=931.74 mL

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Elena-2011 [213]

Explanation:

It is given that,

The time period of artificial satellite in a circular orbit of radius R is T. The relation between the time period and the radius is given by :

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The radius of the orbit in which time period is 8T is R'. So, the relation is given by :

(\dfrac{T}{T'})^2=(\dfrac{R}{R'})^3

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Calculate the molarity of a sugar solution if 4 liters of the solution contains 12 moles of sugar.
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Answer:

3M

Explanation:

Molarity is one of the measures of the molar concentration of a solution, which can be calculated by using the formula below:

Molarity = number of moles ÷ volume

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Molarity = n/V

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Determine the oxidation number of each element in these compounds or ions. (a) au2(seo4)3 (gold(iii) selenate) au = se = o = (b)
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<span>                                                    Au</span>₂(SeO₄)₃

                                         O = -2 × 4 = -8
                                             Se  =  + 6
So,
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Means (SeO₄) contains -2 charge, Now multiply -2 by 3
                                             
                                             -2 ₓ 3 = -6
Means,
                             Au₂ + (-6) = 0
               
                            Au₂  = +6
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                            Au  = +3
Result:
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Cyanide (CN⁻) contains -1 charge,
So,
                              N  =  -3
                              C  =  +2
Then,
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                                               Ni - 2  =  0
Or,
                                                     Ni =  +2
Result:
                            N  =  -3
                            C  =  +2
                           Ni  =  +2




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