1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ASHA 777 [7]
2 years ago
13

The equilibrium of 2H 2 O(g) 2H 2 (g) + O 2 (g) at 2,000 K has a Keq value of 5.31 x 10-10. What is the Keq expression for this

system? (Enter subscripts after the letters: for example, H2O = Hs2O. Also, dont forget to use proper chemical shorthand for chemical symbols. For instance, chlorine = Cl but not cl or cL.)
Chemistry
2 answers:
melomori [17]2 years ago
4 0

Answer : The equilibrium constant expression will be,

k_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}

Explanation :

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

The given balanced chemical reaction is,

2H_2O(g)\rightleftharpoons 2H_2(g)+O_2(g)

So, the equilibrium constant expression will be,

k_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}

nevsk [136]2 years ago
3 0

Answer:

5.31*10^{-10} = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}

Explanation:

For a chemical reaction, equilibrium is a state at which the rate of the forward reaction equals that of the reverse reaction. The equilibrium constant Keq is a parameter characteristic of this state which is expressed as a ratio of the concentration of the products to that of the reactants.

For a hypothetical reaction:

xA + yB ⇄ zC

The equilibrium constant is :

Keq = \frac{[A]^{x}[B]^{y}}{[C]^{z} }

The given reaction involves the decomposition of H2O into H2 and O2

2H_{2}O\rightleftharpoons 2H_{2} + O_{2}

The equilibrium constant is expressed as :

Keq = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}

Since Keq = 5.31*10^-10

5.31*10^{-10} = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}

You might be interested in
If a little old lady is doing 98.3 kilometers/hour, will she get a speeding ticket if the speed limit is 55 miles / hour? [USE:
shutvik [7]

Answer:

It is possible she could get one.

Explanation:

To solve this problem we need to convert 98.3 kilometers/hour to miles/hour.

In other words, we <u>convert km to mi</u>, to do so we multiply 98.3 km by a <em>conversion factor</em>, putting the unit we want to have in the numerator, and the unit we want to convert in the denominator:

  • 98.3 km * \frac{1000m}{1km} *\frac{100cm}{1m}*\frac{1in}{2.54cm} *\frac{1ft}{12in} *\frac{1mi}{5280ft} = 61 mi

Given that the little old lady is doing 61 miles/hour, she could get a speeding ticket.

7 0
3 years ago
A sample of ammonium chloride (NH4Cl) has 9.8 moles. How many atoms of hydrogen are in the sample?
blondinia [14]

2.360 × 10^25

Explanation:

The only issue that may arise from asking a question like this is not understanding mole ratios:

Imagine 1 mol of CO2:

You need 1 mol of the end result. In the end result, you have:

1 Carbon

2 Oxygens

When you're trying to get 1 mol of the final compound, you need to have:

1 mol Carbon

2 mol Oxygen

If this doesn't make sense, Khan Academy has insightful videos showing how this works.

So, for NH4Cl, ignore everything but the H. We don't care about them.

You need 4 hydrogens to get 1 NH4Cl, so multiply whatever mole value you're given by 4. That's how many moles of hydrogen there are.

9.8 mol × 4 = 39.2mol H

So the next question is, <em>what</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>mole</em><em>?</em><em> </em><em> </em>The answer to this question is the same as asking <em>what</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>dozen</em><em>?</em> Well, it's just a number of things. Instead of 12, like a dozen, it's 6.02×10²³. This is called Avogadro's Number.

So say you have two dozen. You'll do 2 × 12, right?

Say you have 39.2moles. Apply the same idea, except with Avogadro's Number instead of 12:

39.2 × 6.02×10²³ = 2.360 × 10^25

So what <em>is</em><em> </em>this number? It's how many <em>things</em><em> </em>are in 39.2moles. We were calculating individual hydrogens, which are atoms, so this number represents how many atoms there are in 39.2moles.

6 0
3 years ago
2. A sample of a gas is occupying a 1500 mL container at a pressure of 3.4 atm and a temperature of 25
lora16 [44]

2. The new pressure, given the data is 3.0 atm

3. The new temperature in K is 361 K

4. The new temperature in K is 348 K

<h3>2. How to determine the new pressure</h3>
  • Initial volume (V₁) = 1500 mL
  • Initial pressure (P₁) = 3.4 atm
  • Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K
  • New temperature (T₂) = 75 °C = 75 + 273 = 348 K
  • New Volume (V₂) = 2000 mL
  • New pressure (P₂) = ?

The new pressure of the gas can be obtained by using the combined gas equation as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

(3.4 × 1500) / 298 = (P₂ × 2000) / 348

Cross multiply

P₂ × 2000 × 298 = 3.4 × 1500 × 348

Divide both sides by 2000 × 298

P₂ = (3.4 × 1500 × 348) / (2000 × 298)

P₂ = 3.0 atm

<h3>3. How to determine the new temperature</h3>
  • Initial volume (V₁) = 450 mL
  • Initial pressure (P₁) = 167 KPa
  • Initial temperature (T₁) = 295 K
  • New pressure (P₂) = 230 KPa
  • New Volume (V₂) = 400 mL
  • New temperature (T₂) =?

The new temperature of the gas can be obtained by using the combined gas equation as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

(167 × 450) / 295 = (230 × 400) / T₂

Cross multiply

T₂ × 167 × 450 = 295 × 230 × 400

Divide both sides by 167 × 450

T₂ = (295 × 230 × 400) / (167 × 450)

T₂ = 361 K

<h3>4. How to determine the new temperature</h3>
  • Initial volume (V₁) = 3.6 L
  • Initial pressure (P₁) = 9.2 atm
  • Initial temperature (T₁) = 298 K
  • New Volume (V₂) = 5.3 L
  • New pressure (P₂) = 7.3 atm
  • New temperature (T₂) =?

The new temperature of the gas can be obtained by using the combined gas equation as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

(9.2 × 3.6) / 298 = (7.3 × 5.3) / T₂

Cross multiply

T₂ × 9.2 × 3.6 = 298 × 7.3 × 5.3

Divide both sides by 9.2 × 3.6

T₂ = (298 × 7.3 × 5.3) / (9.2 × 3.6)

T₂ = 348 K

Learn more about gas laws:

brainly.com/question/6844441

#SPJ1

7 0
2 years ago
How many grams of carbon dioxide are produced when 255 grams of octane (C3H18) combust?
dezoksy [38]

Answer:

787.3 g of CO₂

Explanation:

The combustion of octane is this one:

2C₈H₁₈  +  25O₂  →   16CO₂  +  18H₂O

2 moles of octane react to 25 moles of oxygen in order to produce 16 moles of CO₂ and 18 moles of water.

The products in combustion reactions are always CO₂ and H₂O. The oxygen is always a reactant.

We convert mass to moles: 255 g . 1mol /114g = 2.24 moles

2 moles of C₈H₁₈ can produce 16 moles of CO₂

Then, 2.24 moles may produce (2.24 . 16)/2 = 17.9 moles of CO₂

We convert moles to mass:

17.9 mol . 44g/mol = 787.3 g of CO₂

4 0
2 years ago
studying a molecule and trying to determine if it is DNA or RNA. Which kind of molecule is she studying?
NeTakaya
The double helix "The DNA" 

8 0
3 years ago
Other questions:
  • Explain why liquids unlike gases are virtually incompressible
    8·1 answer
  • What state of matter has a defined volume and takes the shape of its container?
    6·1 answer
  • 1. Which of the following metals oxidized by calcium ions?
    9·1 answer
  • How do you calculate the number of neutrons???? please help
    9·1 answer
  • What is conclusive evidence that mixing sugar in water is a physical change
    14·1 answer
  • What is the name of a loop that electricity flows through?
    10·2 answers
  • PLSSSS ANSWER!!!!!!!!!!!!!
    12·2 answers
  • Which model best represents an element?
    11·1 answer
  • A book sits motionless on a table. Which statement is true? Group of answer choices There are no forces acting on the book. The
    6·1 answer
  • Nicotine is a poisonous, addictive compound found in tobacco. A sample of nicotine contains 6.16 mmol of C, 8.56 mmol of H, and
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!