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Alekssandra [29.7K]
3 years ago
8

What is the molality of a 13.82% by mass glucose solution? the molar mass of c6h12o6 is 180.16 g/mol?

Chemistry
2 answers:
Alekssandra [29.7K]3 years ago
6 0

Answer:

The molality is 0.8901m

Explanation:

Let's start defining the molality.

Molality=\frac{MolSolute}{KgOfSolvent}

We also know that in terms of masses :

SoluteMass+SolventMass=SolutionMass (I)

Finally, we define the mass percent as :

MassPercent=\frac{MassOfSolute}{MassOfSolution}.(100)

Using the data of the mass percent we find that :

13.82=\frac{MassOfSolute}{MassOfSolution}.(100)

\frac{MassOfSolute}{MassOfSolution}=0.1382 ⇒ MassOfSolution=\frac{MassOfSolute}{0.1382}    (II)

We know that the molar mass of glucose is 180.16\frac{g}{mol}

Therefore, if we use the mass of 1 mole of glucose (180.16g) in (II) ⇒

MassOfSolution=\frac{180.16g}{0.1382}

MassOfSolution=1303.618g

Now, if we use the equation (I) :

180.16g+SolventMass=1303.618g

SolventMass=1123.458g

1Kg=1000g ⇒ SolventMass=1.1234Kg

We find that 1 mole of glucose (180.16g of glucose) are combined with 1.1234Kg of solvent to obtain 1303.618g of solution which is a 13.82% by mass glucose solution.

If we want to find the molality, we can replaced all the data in the equation of molality :

Molality=\frac{(1Mol)OfGlucose}{(1.1234Kg)OfSolvent}

Molality=0.8901m

We use 1 mol of glucose in the equation (which corresponds to 180.16 g of glucose)

The letter ''m'' is the unit of molality.

FrozenT [24]3 years ago
5 0
13.82 g / 180.16 g/mol = .07671 moles
.07671 moles / (86.18 g / 1000 g/kg) = .8901 molal

Let me know if you have any further questions!

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