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zysi [14]
3 years ago
5

The metric unit of force is the _____. A.newton B.pound C.kilogram D.watt

Physics
2 answers:
noname [10]3 years ago
6 0

Answer:

Option A is the correct answer.

Explanation:

Force = Mass x acceleration

Unit of force = Unit of mass x Unit of acceleration = kg x m/s²

kg m/s² is also called as Newton (N)

Option A is the correct answer.

hammer [34]3 years ago
3 0

Force = mass × acceleration = kg × m/s^2 = Newton

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Answer:

Force = 3.204Newton

Explanation:

Given the following data;

Pressure = 178

Area = 18 mm² to meter = 18/1000 = 0.018 m²

To find the force;

Force = pressure * area

Force = 178 * 0.018

Force = 3.204 Newton.

4 0
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You need to measure the lengthof you driveway.which measuring tool would produce accurate results that would expect to be the sa
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C a meter stick with only centimeters

D a ruler with millimeters and centimeters

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3 years ago
A Subtle Relationship
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Answer:

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Explanation:

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2 years ago
A long, straight wire carrying a current of 2.60 A is placed along the axis of a cylinder of radius 0.500 m and a length of 4.25
shutvik [7]
<h2>Answer:</h2>

0

<h2>Explanation:</h2>

Since the current carrying wire is placed along the axis of the cylinder, according to the right hand rule, the magnetic field will be tangent to the surface of the cylinder. Therefore, there is no magnetic field through the cylinder.

Remember that the magnetic flux through a given area is the total magnetic field passing through that area. Since there is not magnetic field through the cylinder, the total magnetic flux is therefore zero (0).

7 0
3 years ago
A transformer consists of 290 primary windings and 824 secondary windings. Part A: If the potential difference across the primar
jasenka [17]

Answer:

Part 1) Voltage in secondary windings is 61.08 Volts

Part 2) Current in secondary windings is 0.53 Amperes

Explanation:

The potential developed in the primary and secondary winding of a transformer are related as

\frac{N_{p}}{N_{s}}=\frac{V_{p}}{V_{s}}

where

Np no of turns in primary coil

Ns no of turns in secondary coil

Vp Voltage of turns in primary coil

Vs Voltage of turns in secondary coil

Applying values in the formula we get

\frac{290}{824}=\frac{21.5}{V_{s}}\\\\\therefore V_{s}=21.5\times \frac{824}{290}=61.08V

Part 2)

Using Ohm's law the current is given by

I=\frac{V_{s}}{R}\\\\I=\frac{61.089}{115}=0.53A

5 0
3 years ago
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