When we see the words "Which statement ... ", we know right away that there
will be a list of choices, and we're expected to select our answer from that list.
Strangely, the list of answer-choices for this question has been lost.
Similarly, when we see the words "The picture shows ... ", it's hard to fight
the impulse to look around. In the present situation, <em>that's</em> missing too.
If the diver is just standing there, then the reaction force provided by the cliff
against his feet must be exactly equal to his weight. If the vertical forces acting
on the soles of his feet were not balanced, then his feet would be accelerating
vertically.
His weight is (mass) x (gravity) =
(93 kg) x (9.8 m/s²) = <em>911.4 newtons</em> (about 205 pounds) .
That's also the strength of the upward reaction force provided by the cliff.
Answer:
The index of refraction of the liquid is n = 1.33 equivalent to that of water
Explanation:
Solution:-
- The index of refraction of light in a medium ( n ) determines the degree of "bending" of light in that medium.
- The index of refraction is material property and proportional to density of the material.
- The denser the material the slower the light will move through associated with considerable diffraction angles.
- The lighter the material the faster the light pass through the material without being diffracted as much.
- So, in the other words index of refraction can be expressed as how fast or slow light passes through a medium.
- The reference of comparison of how fast or slow the light is the value of c = 3.0*10^8 m/s i.e speed of light in vacuum or also assumed to be the case for air.
- so we can mathematically express the index of refraction as a ratio of light speed in the material specified and speed of light.
- The light passes through a liquid with speed v = 2.25*10^8 m/s :
- The index of refraction of the liquid is n = 1.33 equivalent to that of water.
Please elaborate more on your question so I can help you
Answer:
1.19cm^3 of glycerine
Explanation:
Let Vo= 150cm^3 for both aluminum and glycerine, using expansion formula:
Volume of spill glycerine = change in volume of glycerine - change in volume of aluminum
Volume of glycerine = coefficient of volume expansion of glycerine * Vo* change in temperature - coefficient of volume expansion of Aluminum*Vo* change temperature
coefficient of volume expansion of aluminum = coefficient of linear expansion of aluminum*3 = 23*10^-6 * 3 = 0.69*10^-4 oC^-1
Change in temperature = 41-23 = 18oC
Volume of glycerine that spill = (5.1*10^-4) - (0.69*10^-4) (150*18) = 4.41*10^-4*2700 = 1.19cm3
Answer:
speaker64
--------
34x
Explanation:
64-34
x
speaker
4
2
4
788
- circuit
voltage
100000
x.34
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