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kondor19780726 [428]
2 years ago
10

Define the focus of a concave lens ​

Physics
1 answer:
Sophie [7]2 years ago
8 0

Answer:

<u>Principal</u><u> </u><u>focus</u><u> </u><u>of</u><u> </u><u>concav</u><u>e</u><u> </u><u>lens</u><u> </u><u>-</u><u> </u>

★ The point at which rays parallel to principal axis coming from infinity appear to converge after being refracted from concave lens is called the principal focus of concave lens.

<em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em>

• <u>Additional</u><u> information</u><u> </u><u>-</u><u> </u>

★ Principal focus - A number of rays parallel to the principal axis after reflection from a concave mirror meet at a point on the principal axis or appear to come from a point after reflection from a convex mirror on the principal axis. This is called principal focus.

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How much energy is produced if you have a current carrying a charge of 0.0006 C running 8.0 V?
sweet-ann [11.9K]

Answer:

Energy= Workdone = 1/2QV

= 1/2x0.0006 x 8

=2.4x10-³J.

5 0
2 years ago
When two systems in contact are not at the same temperature, _____ occurs.
Korvikt [17]
The answer is "heat transfer."
6 0
2 years ago
Write a linear equation that expresses the relationship between the temperature in degrees Celsius (C) and degrees Fahrenheit (F
UkoKoshka [18]

Answer:

\displaystyle F=\frac{9}{5}C+32

\displaystyle C=\frac{5}{9}(F-32)

Explanation:

<u>Temperature Units Conversion </u>

The conversion formula between Celsius and Fahrenheit temperature scales is well-known. But we'll use the provided data to derive the formula. Let's model the relationship between Fahrenheit (F) and Celsius (C) as a linear function like

F=mC+b

Where m and b must be computed according to the pair of conditions given. The values for each temperature scale are (C,F)=(0,32) and (100,212). Replacing the first value

32=m\times 0+b

It means that  

b=32

By using the second point

212=m\times 100+32

Solving for m

\displaystyle m=\frac{212-32}{100}=\frac{180}{100}

Simplifying

\displaystyle m=\frac{9}{5}

So, the conversion formula is

\displaystyle F=\frac{9}{5}C+32

Which is the widely known formula for temperature conversion

Solving for C, we get the inverse relation

\boxed{\displaystyle C=\frac{5}{9}(F-32)}

3 0
3 years ago
Where does the energy come from in a nuclear fission reaction?
poizon [28]

Answer:ni

Explanation:

nnn

4 0
3 years ago
What beat frequencies are possible with tuning forks of frequencies 255, 258, and 260 hz ?
zavuch27 [327]

Possible beat frequencies with tuning forks of frequencies 255, 258, and 260 Hz are 2, 3 and 5 Hz respectively.

The beat frequency refers to the rate at which the volume is heard to be oscillating from high to low volume. For example, if two complete cycles of high and low volumes are heard every second, the beat frequency is 2 Hz. The beat frequency is always equal to the difference in frequency of the two notes that interfere to produce the beats. So if two sound waves with frequencies of 256 Hz and 254 Hz are played simultaneously, a beat frequency of 2 Hz will be detected. A common physics demonstration involves producing beats using two tuning forks with very similar frequencies. If a tine on one of two identical tuning forks is wrapped with a rubber band, then that tuning forks frequency will be lowered. If both tuning forks are vibrated together, then they produce sounds with slightly different frequencies. These sounds will interfere to produce detectable beats. The human ear is capable of detecting beats with frequencies of 7 Hz and below.

A piano tuner frequently utilizes the phenomenon of beats to tune a piano string. She will pluck the string and tap a tuning fork at the same time. If the two sound sources - the piano string and the tuning fork - produce detectable beats then their frequencies are not identical. She will then adjust the tension of the piano string and repeat the process until the beats can no longer be heard. As the piano string becomes more in tune with the tuning fork, the beat frequency will be reduced and approach 0 Hz. When beats are no longer heard, the piano string is tuned to the tuning fork; that is, they play the same frequency. The process allows a piano tuner to match the strings' frequency to the frequency of a standardized set of tuning forks.

Learn more about  beat frequency here : brainly.com/question/14157895

#SPJ4

7 0
2 years ago
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