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borishaifa [10]
3 years ago
13

70,030,000 in scientific notation

Mathematics
1 answer:
mafiozo [28]3 years ago
4 0
<span>70,030,000 = 7.003 x 10^9
............................................</span>
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Find the truth value in each statement (true or false). 1.) C, E, and D are coplanar. 2.) B and E are collinear.
MaRussiya [10]
You need to post the diagram that goes to this question. But here's a hint so you can do this on your own co planar means that the points are in the same plane and collinear means that the points are on the same line.
3 0
4 years ago
Find the function y = f(t) passing through the point (0, 18) with the given first derivative.
monitta

Answer:

\displaystyle y = \frac{t^2}{16} + 18

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>

  • Functions
  • Function Notation
  • Coordinates (x, y)

<u>Calculus</u>

Derivatives

Derivative Notation

Antiderivatives - Integrals

Integration Constant C

Integration Rule [Reverse Power Rule]:                                                                   \displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Property [Multiplied Constant]:                                                             \displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Point (0, 18)

\displaystyle \frac{dy}{dt} = \frac{1}{8} t

<u>Step 2: Find General Solution</u>

<em>Use integration</em>

  1. [Derivative] Rewrite:                                                                                         \displaystyle dy = \frac{1}{8} t\ dt
  2. [Equality Property] Integrate both sides:                                                        \displaystyle \int dy = \int {\frac{1}{8} t} \, dt
  3. [Left Integral] Integrate [Integration Rule - Reverse Power Rule]:                 \displaystyle y = \int {\frac{1}{8} t} \, dt
  4. [Right Integral] Rewrite [Integration Property - Multiplied Constant]:           \displaystyle y = \frac{1}{8}\int {t} \, dt
  5. [Right Integral] Integrate [Integration Rule - Reverse Power Rule]:              \displaystyle y = \frac{1}{8}(\frac{t^2}{2}) + C
  6. Multiply:                                                                                                             \displaystyle y = \frac{t^2}{16} + C

<u>Step 3: Find Particular Solution</u>

  1. Substitute in point [Function]:                                                                         \displaystyle 18 = \frac{0^2}{16} + C
  2. Simplify:                                                                                                             \displaystyle 18 = 0 + C
  3. Add:                                                                                                                   \displaystyle 18 = C
  4. Rewrite:                                                                                                             \displaystyle C = 18
  5. Substitute in <em>C</em> [Function]:                                                                                \displaystyle y = \frac{t^2}{16} + 18

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Integration

Book: College Calculus 10e

4 0
3 years ago
What’s the answer did anyone figure it out ?
olya-2409 [2.1K]

Answer:

NAswer to what

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Match each equation to a solution.<br> 2X=64
Marysya12 [62]
X=32

2x=64 divide each side by 2
5 0
3 years ago
Find the distance of each the following lines from the origin.
meriva

Answer:

Step-by-step explanation:

3x+y−7=0 and x+2y+9=0

write in the form y=mx+c

i.e.y=−3x+7,y=  

2

−x

​  

−  

2

9

​  

 

∴m  

1

​  

=−3 and m  

2

​  

∓−  

2

1

​  

 

tan(A−B)=  

∣

∣

∣

∣

∣

​  

 

1+tanAtanB

tanA−tanB

​  

 

∣

∣

∣

∣

∣

​  

 

∣

∣

∣

∣

∣

​  

 

1+(−3)(−y  

2

​  

)

−3−(−y  

2

​  

)

​  

 

∣

∣

∣

∣

∣

​  

 

=  

∣

∣

∣

∣

∣

​  

 

5/2

−5/2

​  

 

∣

∣

∣

∣

∣

​  

=1

∴ Angle b/w then is tan  

−1

(1)=45  

∘

 

=  

4

π

​

7 0
3 years ago
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