Calculate the specific heat capacity of a piece of ice if 1.30 kg of the wood absorbs 6.75×104 joules of heat, and its temperatu
2 answers:
Answer:
2076.9 J/kg°C
Explanation:
The equation needed here is:
, where q is the energy in Joules, m is the mass in kg, C is the heat capacity, T_f is the final temperature, and T_i is the initial temperature.
Here, we have q = 6.75* J, m = 1.30kg, T_f = 57, and T_i = 32. So:
Solving for C, we get:
C = 2076.9 J/kg°C
Hope this helps!
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Answer:
Here's what I get
Explanation:
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It is homogeneous because it is a solution. There is only one phase: the liquid phase. You cannot see the pigments as separate phases.
You can separate the pigments by paper, thin layer, or column chromatography.
Many schools use paper chromatography, because paper is cheap.
As the mixture of pigments follows the solvent up the paper, they separate into different coloured bands according to their attractive forces to the cellulose in the paper.
The chlorophylls are strongly attracted to the paper, so they don't travel very far.
The nonpolar carotene molecules have little attraction to the polar cellulose, so they are carried along by the solvent front.
