Calculate the specific heat capacity of a piece of ice if 1.30 kg of the wood absorbs 6.75×104 joules of heat, and its temperatu

Question

Bond [772]

2 years ago

11

Calculate the specific heat capacity of a piece of ice if 1.30 kg of the wood absorbs 6.75×104 joules of heat, and its temperatu

re changes from 32 ºC to 57 ºC.

Chemistry

2 answers:

spayn [35] · Answer 1 · 2022-02-08T01:07:58+03:00

Answer:

1.8 J/ g ∘ C

Explanation:

A substance's specific heat tells you how much heat much either be added or removed from 1 g of that substance in order to cause a 1 ∘ C change in temperature.

The equation that establishes a relationship between specific heat, heat added or removed.

Lunna [17] · Answer 2 · 2022-02-08T02:23:19+03:00

Answer:

2076.9 J/kg°C

Explanation:

The equation needed here is:

$q=mC(T_f-T_i)$ , where q is the energy in Joules, m is the mass in kg, C is the heat capacity, T_f is the final temperature, and T_i is the initial temperature.

Here, we have q = 6.75* $10^4$ J, m = 1.30kg, T_f = 57, and T_i = 32. So:

$6.75*10^4=1.30*C*(57-32)$

Solving for C, we get:

C = 2076.9 J/kg°C

Hope this helps!