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Artist 52 [7]
3 years ago
13

What are the magnitude (size) and direction of the cumulative force acting on the car shown in the picture A. 30 N to the right

B. 2500 N down C. 30 N to the left D. 3500 N up

Chemistry
2 answers:
Komok [63]3 years ago
7 0

Answer:30n to the right

Explanation:

UNO [17]3 years ago
4 0

Answer: The correct answer is option(A).

Explanation:

Total forces exerting on the car = F

F_r=50 N= Force on car exerting in right direction

F_l=20 N= Force on car exerting in left direction

F_u=2500 N= Force on car exerting in upward direction

F_d=2500 N= Force on car exerting in downward direction

F=F_r+F_l+F_u+F_d

(-F_u)=F_d (negative sign shows the direction)

Since, upward force are equal in magnitude but opposite in direction by which they will balance out each other.so, the net force car will be due to two forces F_r and F_l

F=F_r+F_l=50 N+(-20 N)=30 N(negative shows the direction)

The magnitude (size) and direction of the cumulative force acting on the car will 30 N towards right direction.Hence, correct answer is option(A).

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