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2 years ago

Which expression is equivalent to 1/2x + 8

Mathematics

1 answer:

elena55 [62]2 years ago

5 0

Answer:

1/2( x+16)

Step-by-step explanation:

1/2x + 8

Factor out 1/2

1/2*x + 1/2 *16

1/2( x+16)

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3. Which linear equation corresponds to the line graph?

iogann1982 [59]

Answer:

Y=1/3x

Step-by-step explanation:

1) there is no y intercept as x=0 when y=0 so that rules out y=x-2

2) next, we will use the formula for slope to find the value of m

Y2-Y1/X2-X1

Where y2=-1

Y1=0

X2=-3

X1=0

-1-0/-3-0=-1/-3

Aka 1/3

So y=1/3x

Hope this helps!

3 0

3 years ago

Factor completely x2 + 20x − 36.

vodomira [7]

Answer:

Prime

Step-by-step explanation:

x² + 20x − 36

You must find a pair of numbers that multiply to give -36 and add to give +20.

The likely candidates are 2 and 18, and they must have opposite signs to give a negative product.

+2 × (-18) = -36; +2 + (-18) = -16

-2 × 18 = -36; -2 + 8 = +16

Neither combination gives +20 as the sum.

The expression can't be factored with rational numbers.

The expression is prime.

5 0

3 years ago

29, 20, 36, 44, 30, 32, and 40.

tamaranim1 [39]

Answer:

can't understand the question.

7 0

3 years ago

Read 2 more answers

In a triangle the measurement of an exterior angle is always greater than the measurement of the adjacent interior angle.what is

Mariana [72]

The measure of and adjacent angle is less than the measure of the exterior angle

7 0

2 years ago

What term is 1/1024 in the geometric sequence,-1,1/4,-1/6..?

Trava [24]

Answer:

$\large\boxed{\text{sixth term is equal to}\ \dfrac{1}{1024}}$

Step-by-step explanation:

The explicit formula for a geometric sequence:

$a_n=a_1r^{n-1}$

$a_n$ - n-th term

$a_1$ - first term

$r$ - common ratio

$r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=...=\dfrac{a_n}{a_{n-1}}$

We have

$a_1=-1,\ a_2=\dfrac{1}{4},\ a_3=-\dfrac{1}{6},\ ...$

The common ratio:

$r=\dfrac{\frac{1}{4}}{-1}=-\dfrac{1}{4}\\\\r=\dfrac{-\frac{1}{6}}{\frac{1}{4}}=-\dfrac{1}{6}\cdot\dfrac{4}{1}=-\dfrac{2}{3}\neq-\dfrac{1}{4}$

<h2>It's not a geometric sequence.</h2>

If $a_3=-\dfrac{1}{16}$ then the common ratio is $r=\dfrac{-\frac{1}{16}}{\frac{1}{4}}=-\dfrac{1}{16}\cdot\dfrac{4}{1}=-\dfrac{1}{4}$

Put to the explicit formula:

$a_n=-1\left(-\dfrac{1}{4}\right)^{n-1}$

Put $a_n=\dfrac{1}{1024}$ and solve for <em>n </em>:

$-1\left(-\dfrac{1}{4}\right)^{n-1}=\dfrac{1}{1024}\qquad\text{use}\ a^n:a^m=a^{n-m}\\\\-\left(-\dfrac{1}{4}\right)^n:\left(-\dfrac{1}{4}\right)^1=\dfrac{1}{1024}\\\\-\left(-\dfrac{1}{4}\right)^n\cdot(-4)=\dfrac{1}{1024}\\\\(4)\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{1024}\qquad\text{divide both sides by 4}\ \text{/multiply both sides by}\ \dfrac{1}{4}/\\\\\left(-\dfrac{1}{4}\right)^n=\dfrac{1}{4096}\\\\\dfrac{(-1)^n}{4^n}=\dfrac{1}{4^6}\qquad n\ \text{must be even number. Therefore}\ (-1)^n=1$

$\dfrac{1}{4^n}=\dfrac{1}{4^6}\iff n=6$

5 0

3 years ago