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m_a_m_a [10]
3 years ago
8

When 2 grams of powdered lead (IV) oxide was added to 100 cm3 of hydrogen peroxide, water and oxygen were produced. Lead (IV) ox

ide was not used up in the reaction. Based on the information, which of the following is likely to decrease the rate of formation of the products?
Replacing the powdered lead oxide with its large crystals
Removing lead (IV) oxide from the reaction mixture
Using 50 cm3 of hydrogen peroxide
Using 1.0 gram of lead (IV) oxide
Chemistry
2 answers:
STALIN [3.7K]3 years ago
8 0

Answer:

Replacing the powdered lead oxide with its large crystals

Explanation:

Powdered lead (IV) oxide has larger surface area than its crystal form. Surface area increases the rate of the reaction. Larger the surface larger is the effective collision thereby faster reaction completion.

Using large of crystals of lead (IV) oxide is likely to decrease the rate of formation of the products.

andre [41]3 years ago
7 0

Answer:

Replacing the powdered lead oxide with large crystals

Explanation:

The large crystals have less surface area exposed to the other reagents than the powdered  lead oxide. High surface area leads to a high rate of reaction thus the products are formed faster, while a low surface area leads to a lower rate of reaction since the reagent is less exposed to the other reagents.

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A technician measures the weight of a reagent . The weight is 3269 g. What is the weight in kilograms ? Write your answer as a d
Georgia [21]

Answer:

3.269 kg

Explanation:

1000g = 1 kg. Since kg is the larger unit, you need to divide by 1000 to get kilograms. You can do the problem as a unit conversion:

3269 g × <u>1 kg</u>  =  3.269 kg

                1000g

Hope this is helpful!

5 0
3 years ago
Benzene is an organic chemical compound with the molecular formula C6H6. In the benzene molecule, carbon atoms form a ring with
Sergeu [11.5K]

Answer:

sp^2

Explanation:

Hello,

The six-carbon benzene ring contains two types of bonds: C-C and C-H bonds, that are  sp^2-hybridized σ bonds, and the six π bonds that form the aromatic ring. The σ bonds form from one s orbital and two p orbitals from each carbon, which then bond the carbon to the two carbons on either side and the carbon's single hydrogen. The remaining p orbital from each carbon atom sticks out above and below the plane of the ring; these p orbitals overlap sideways, rather than lengthwise, to form the aromatic π bond system.

Best regards.

8 0
2 years ago
How many moles of NaCl are created as a result of decomposing 12 grams of NaClO3? (molar mass of Na=23, Cl=35, O=16)
Harman [31]

Answer: 0.113 moles of NaCl are created as a result of decomposing 12 grams of NaClO_3.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}   

\text{Moles of} NaClO_3=\frac{12g}{106.5g/mol}=0.113moles

The balanced chemical equation for decomposition of NaClO_3 is:

2NaClO_3\rightarrow 2NaCl+3O_2  

According to stoichiometry :

2 moles of NaClO_3 give = 2 moles of NaCl

Thus 0.113 moles of NaClO_3 give =\frac{2}{2}\times 0.113=0.113moles  of NaCl

Thus 0.113 moles of NaCl are created as a result of decomposing 12 grams of NaClO_3.

8 0
2 years ago
Which of the following would dissolve in water, and why?
Oduvanchick [21]

Answer:

It should be acetic acid.

Explanation:

When you have ionic bonds, the ionic bonds will always be water soluble; the polarity doesn't matter for this case.

4 0
3 years ago
In the combined gas law, if the volume is decreased, what happens to the temperature if pressure remains constant?
Flura [38]

The correct answer is A. In the combined gas law, if the volume is decreased and the pressure is constant, then the temperature decreases.

 <span>P1V1/ T1 = P2V2 / T2</span>

 <span>Assume the volume decrease by half; V2 = V1/2</span>

 <span>P1V1/ T1 = P2V1 /2 T2</span>

 <span>Cancelling terms,</span>

 <span>1/T1 = 1/2 T2</span>

T2 = T1/2

 <span>Thus, the temperature decreased.</span>

8 0
3 years ago
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