Answer:
CuSO4 (aq) + Zn ( s ) ⟶ ZnSO4 (aq) + Cu (s): single displacement.
Cu(NO3)2(aq) + 2NaOH(aq) ⟶ Cu(OH)2(s) + 2NaNO3 (aq): Double displacement.
CuO(s) + H2SO4 (aq) ⟶ CuSO4 (aq) + H2O( l ): Double displacement.
Cu(s) + 4HNO3 (aq) ⟶ Cu(NO3)2 (aq) + 2NO2(aq) + 2H2O(l): Redox
Cu(OH)2 (s) Δ −→ CuO (s) + H2O(g): Decomposition.
Explanation:
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In this case, for the given chemical reactions, we obtain:
CuSO4 (aq) + Zn ( s ) ⟶ ZnSO4 (aq) + Cu (s): single displacement as the zinc metal is displacing copper in copper (II) sulfate.
Cu(NO3)2(aq) + 2NaOH(aq) ⟶ Cu(OH)2(s) + 2NaNO3 (aq): Double displacement as sodium is getting with nitrate and copper (II) with hydroxide.
CuO(s) + H2SO4 (aq) ⟶ CuSO4 (aq) + H2O( l ): Double displacement as the oxygen in the cupper (II) oxide turns out with the hydrogen and as a result, copper (II) sulfate is formed.
Cu(s) + 4HNO3 (aq) ⟶ Cu(NO3)2 (aq) + 2NO2(aq) + 2H2O(l): Redox since the copper joins NO3 but at the same time NO2 is released (Nitrogen goes from 5+ to 4+).
Cu(OH)2 (s) Δ −→ CuO (s) + H2O(g): Decomposition as copper (II) hydroxide is separated into copper (II) oxide and water.
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