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trasher [3.6K]
3 years ago
6

Here is a pic of me I'm ugly i dont have all my pics of me anymore lost it all

Chemistry
2 answers:
Hunter-Best [27]3 years ago
6 0

ur hair is pretty tho

Elden [556K]3 years ago
3 0

Answer:

u looking so beautiful

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The standard lab thermometer in a high school science lab contains
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Distilled water.high school Lab
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Methane gas is burned
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Yes it is burned and I need to do that question as well for my class
3 0
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A spring running horizontally has areas with the coils closer together and areas with them farther apart. A label A points to ar
Margaret [11]

Answer:

compressions: a

rarefactions: b

wavelength: c

Explanation:

i got it right

5 0
3 years ago
Please help<br> Explain why a molecule that has polar bonds can be a polar molecule.
Zepler [3.9K]

Answer:

Explanation:

Well, obviously a molecule with polar bonds can be polar in itself. It's like saying I am an atheltic person who can just reach the basketball rim with my head and also I can dunk.

But if the question is how can a molecule that in non-polar have polar bonds, well, its because the polar bonds' dipole cancels each other out. It's like a tight rope. If a person pulls in one direction, it intuitively, the rope would go in that direction. However, if a person pulls in the other direction with the same amount of force, the rope stays still. This is the same case. Although molecules can have different electronegativities, the pull of electrons in one direction is cancelled out by a pull in the opposite direction, making the net dipole 0.

This is common for main VSERP shaped molecules like linear, trigonal planar, tetrahedral, trigonal bipyramidal, and octahedral.

8 0
3 years ago
A sample of 42 mL of carbon dioxide gas was placed in a piston in order to maintain a constant 101 kPa of pressure.
Lilit [14]

Answer:

The answer to your question is 33.4 ml

Explanation:

Data

volume 1 = V1 = 42 ml

temperature 1 = T1 = 20°C

temperature 2 = T2 = -60°C

Volume 2 = V2 = x

Process

1.- Convert celsius to kelvin

T1 = 20 + 273 = 293°K

T2 = -60 + 273 = 233°K

2.- Use the Charles' law to solve this problem

               \frac{V1}{T1} = \frac{V2}{T2}

Solve for V2

                V2 = \frac{V1T2}{T1}

3.- Substitution

               V2 = \frac{(42)(233)}{293}

4.- Simplification

                V2 = \frac{9786}{293}

5.- Result

                V2 = 33.4ml

3 0
3 years ago
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