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swat32
3 years ago
10

What is 63/120 simplified?

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
8 0
It’s 21/40 hope I helped
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What value of A in this equation y=(9A-7)x would give a line with the slope -5?
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0, I put y=(0-7)x into a graphing calculator

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The base of a pyramid is a square whose perimeter is 936936 m. what is the length of each side of this​ square?
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936936 is the perimeter and perimeter of a square is 4 times the length of one of the sides. therefore, you divide 936936 by 4 and get your answer, which is 234234.
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a painter bought 8 gallons of paint just enough to cover 2 rooms. One room is twice the size of the other and requires only 2 co
e-lub [12.9K]
So, he's got 8 gallons of paint, to paint the two rooms, of the two rooms, one is twice as big as the other

now, "x" is how many gallons to paint the larger room with only one coat, however, the larger room uses 2 coats, so, the larger room uses 2x of paint
now, the client declined to paint the smaller one

so hmmm as I read... well, we dunno how many coats will go to the smaller room for one, we know the larger will use 2 coats, or 2x.. if we assume the smaller room was going to use say 1 coat or 1/2x

then one can say the painter bought enough for both rooms, 1coat for the small one and 2coats for the larger one

so, the paint the larger room, you'll 2x of paint, for 2coatsand to paint the smaller room, you'll need 1/2 x, because x gallons is how much is needed for the larger room, but the larger room is twice as big, thus the smaller room uses 1/2 of that in gallons

thus, with those assumptions, that the small room will use only 1 coat
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now, the client decides to skip the smaller roomso, the painter will only need 2x gallons then

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3 0
2 years ago
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Nostrana [21]

Answer:

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Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.

Step-by-step explanation:

The true statements are:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.  

Lets discuss each option one by one:

Over the interval [1, 3], the local minimum is 0

This is a false statement. Look at the graph. The minimum point given is (3.4,-8). Therefore the local minimum is -8 not 0

Over the interval [2, 4], the local minimum is –8.

This statement is true because the given minimum point is(3.4, -8). Thus the  local minimum is -8 which is true

Over the interval [3, 5], the local minimum is –8.

According to the given minimum point, the local minimum  is -8 which is true

Over the interval [1, 4], the local maximum is 0.

Look at the graph. The maximum point given is (2,0). Thus this statement is true because local maximum is 0.

Over the interval [3, 5], the local maximum is 0.

This is a false statement because there is no maximum point

8 0
3 years ago
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Show that the curve x = 7 cos(t), y = 5 sin(t) cos(t) has two tangents at (0, 0) and find their equations.
elena-s [515]
Y= 5 y =7 thats the smaller slip and larger
8 0
3 years ago
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