I don’t think you can do that
Answer:
Step-by-step explanation:
Part A
xf = xo + vo* t + 1/2 a*t^2 Subtract xo
xf - xo = 0*t + 1/2 a*t^2 multiply by 2
2(xf - xo) = at^2 divide by t^2
2(xf - xo ) / t^2 = a
Part B
Givens
xo =0
vo = 0
a = 10 m/s^2
xf = 120 m
Solution
xf = xo + vo* t + 1/2 a*t^2 Substitute the givens
120 = 0 + 0 + 1/2 * 10 * t^2 Multiply by 2
120*2 = 10* t^2
240 = 10*t^2 Divide by 10
240/10 = t^2
24 = t^2 take the square root of both sides.
√24 = √t^2
t = √24
t = √(2 * 2 * 2 * 3)
t = 2√6
Answer:
(-0.5, -1)
Step-by-step explanation:
To find the midpoint add the coordinates then divide by 2
x = (2 + -1)/2
x = 1/2 = 0.5
y = (3 + -5)/2
y = -1
(-0.5, -1)
Answer:
√20
Or
2√5
Step-by-step explanation:
It is very easy just substitute
It will be:
