A student makes up a 0. 6 M solution of acetic acid then its pOH of this solution is 13.77
Calculation ,
A figure expressing the acidity or alkalinity of a solution on a logarithmic scale on which 7 is neutral, lower values are more acid and higher values more alkaline.
We have to find pH of the acetic acid .
[ ] = 0. 6
pH = -㏒[ ]
pH = -㏒ [ 0. 6 ]
pH = 0.22
pH + pOH = 14
pOH = 14 - pOH = 14 - 0.22 = 13.77
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Answer:
Explanation:
At , the heat of vaporization of water is given by:
The water here condenses and gives off heat given by the product between its mass and the heat of vaporization:
The block of aluminum absorbs heat given by the product of its specific heat capacity, mass and the change in temperature:
According to the law of energy conservation, the heat lost is equal to the heat gained:
or:
Rearrange for the final temperature:
We obtain:
Then:
Answer:
1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 2NaC₂H₃O
Explanation:
1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 1NaC₂H₃O₂
1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 2NaC₂H₃O₂
(on the reactant side there are two molecules of C₂H₃O₂ and 2 atoms of Na, so in order to balance that we put the coefficient 2 on NAC₂H₃O₂)
So the final product is
1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 2NaC₂H₃O₂
Hey there!
Here is your answer:
<u><em>The proper answer to this question is option D "sec-butyl bromide".</em></u>Reason:
<u><em>S</em></u><span><u><em>ec-butyl bromide looks often like this:</em></u>
<em>Therefore the answer is option D!</em>If you need anymore help feel free to ask me!
Hope this helps!
~Nonportrit</span>