Because it a neutral atom, try taking aluminum foil and putting on a hot stove, it will heat up as fast as itcools down.
Answer is: defining the components of nuclei.
Rutherford theorized that atoms have their charge concentrated in a very small nucleus.
This was famous Rutherford's Gold Foil Experiment: he bombarded thin foil of gold with positive alpha particles (helium atom particles, consist of two protons and two neutrons).
Rutherford observed the deflection of alpha particles on the photographic film and notice that most of alpha particles passed straight through foil.
That is different from Plum Pudding model, because it shows that most of the atom is empty space.
Rutherford conducted research that led to the first splitting of the atom in a nuclear reaction.
Answer:
The answer to your question is 8.2 g of TiF₄
Explanation:
Data
Theoretical yield = ?
mass of Ti = 5 g
mass of F₂ = 5 g
Balanced chemical reaction
Ti(s) + 2F₂ (g) ⇒ TiF₄(g)
Process
1.- Calculate the Molar mass of reactants and products
Ti = 48 g
2F₂ = 2( 19 x 2) = 76 g
TiF₄ = 48 + 76 = 124 g
2.- Calculate the limiting reactant
theoretical proportion Ti/F₂ = 48/76 = 0.63
experimental proportion Ti/F₂ = 5/5 = 1
Conclusion The limiting reactant is F₂ because the experimental proportion was lower than the theoretical proportion.
3.- Calculate the theoretical yield using the mass of F₂
76 g of F₂ --------------- 124 g of TiF₄
5 g of F₂ --------------- x
x = (5 x 124) / 76
x = 8.15 g of TiF₄
1) Recording the change in pressure when heating an inflated tire
Explanation:
This happens because with an increase in temperatures, the kinetic energy of the gas in the tire increases. The increase in kinetic energy means the molecules move more rapidly. There is an increased rate of collisions between the gas molecules, and increased energy of the collisions, and between the gas molecules and inner walls of the tire hence the increased pressure. Pressure and temperatures and directly proportional s long as the volume of the gas is kept constant.
It is in Group 5A => <u>5</u> valence electrons
