Solution:
we have been asked to sketch a plane containing points E, D and B.
where E and B are collinear with A. It mean all thses three points will fall on a straight line. Also D is a vertex where CD and FD meets.
The sketch has been attched below.
Here as you can see three points are in a staright line and we have another one in whuch two vectors CD and FD are meeting at the vertex D.
Answer:
Step-by-step explanation:
another isosceles triangle
SOH CAH TOA
Cos(x)=Adj/ Hyp
Hyp*Cos(45) = Adj
26 *
= Adj
13
both legs
3 4 6 9 13 18 24 31 39 48 58
+1 +2 +3 +4 +5 +6 +7 +8 +9 +10
22 centimeters
242 ( area ) divided by 11( width) =22 ( length)
Answer: 2v-22
Step-by-step explanation:
2(v)=2v
2(-11)= -22
2v - 22