Answer: 4
Step-by-step explanation:
Given
PA=6, PD=4, BE=5
We know, If PEB is a secant that intersects the circle at E and B and PA be a tangent at A, then
Substitute the given values
Take
Discard
Answer:
Step-by-step explanation:
area of trapezium ABCD
=(16.5+12)/2 \times 15
=(28.5)/2 \times 15
=213.75 cm^2
Area of PQRS
=213.75 \times (\frac{2}{3} )^2\\=213.75 \times\frac{4}{9} \\=95 ~cm^2
area of green portion=213.75-95=118.75 cm²
The vertex will be when the velocity is equal to zero:
df/dx=-12x+24 (using the power rule for differentiation)
df/dx=0 only when:
-12x+24=0 add 12x to both sides
12x=24 divide both sides by 12
x=2, we find the y value to be:
y(2)=-6(2^2)+24*2-20
y(2)=-24+48-20=4
So the vertex is the point (2,4)
And the axis of symmetry is the line x=2
Now if you do not yet do calculus...
The vertex will occur midway between the two zeros.
6x^2-24x+20=0 (using the Quadratic Formula for simplicity)
x=(24±√96)/12
x≈(1.1835, 2.8165)
Now the vertex occurs at the average of the zeros...
x=(1.1835+2.8165)/2=2 (as we saw earlier)
y(2)=4
Vertex is at (2,4) and axis of symmetry is the vertical line x=2
Answer:
First one
Step-by-step explanation:
y = -3x + 5
Make x the subject
3x = 5 - y
x = (5 - y)/3
Interswitch variables
(f^-1)(x) = (5 - x)/3
= 5/3 - x/3
1/2 < 7/15
because
15/ 30 < 14/ 30
(these are equivalent fractions- they have the same denominator so that it is easier to compare)