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OLga [1]
4 years ago
9

Find out the cylinders volume whose height is 3 cm and radius 5cm

Mathematics
2 answers:
Studentka2010 [4]4 years ago
8 0
Volume = πr²h

Volume = π(5)²(3)

Volume = 75π = 235.62 cm³ (nearest hundredth)

----------------------------------------------
Answer: Volume = 235.62 cm³.
----------------------------------------------<span />
irina1246 [14]4 years ago
4 0

Answer:

235.62 give the other person brainliest, they did a bunch of work

Step-by-step explanation:


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Rare Shoes had a regular price of $95, but Jay found them on sale for 50% off.Including the 8% sales tax, what did Jay pay for t
Helga [31]

Answer:

55.1

Step-by-step explanation:

50% of 95 is 47.5

8% of 95 is 7.6

95-47.5+7.6

4 0
3 years ago
A cylinder has a height of 16 cm and a radius of 5 cm. A cone has a height of 12 cm and a radius of 4 cm. If the cone is placed
Rom4ik [11]
To figure out this problem you need to find the area of the cylinder   A= pi r^2 *h

Then find the area of the cone 1/3*pi*r^2 *h

Subtract the two answers
4 0
3 years ago
Which of the following is the solution set of x² + 8x + 12 = 0?<br><br> {2, 6}<br> {-2, -6}<br> {}
Mkey [24]
{-2,-6} because of they are both positive then there is no way you can get 0 by adding and multiplying so they have to be negative
7 0
4 years ago
Read 2 more answers
Please help me!!!!!!!!!!!!!​
monitta

Answer:  see proof below

<u>Step-by-step explanation:</u>

Use the following Half-Angle Identities:    tan (A/2) = (sinA)/(1 + cosA)

                                                                     cot (A/2) = (sinA)/(1 - cosA)

Use the Pythagorean Identity: cos²A + sin²B = 1

Use Unit Circle to evaluate: cos 45° = sin 45° = \frac{\sqrt2}{2}

<u>Proof LHS → RHS</u>

Given:                       cot\ (22\frac{1}{2})^o-tan\ (22\frac{1}{2})^o

Rewrite Fraction:     cot\ (\frac{45}{2})^o-tan\ (\frac{45}{2})^o

Half-Angle Identity:   \dfrac{sin(45)^o}{1-cos(45)^o}-\dfrac{sin(45)^o}{1+cos(45)^o}

Substitute:                  \dfrac{\frac{\sqrt2}{2}}{1-\frac{\sqrt2}{2}}-\dfrac{\frac{\sqrt2}{2}}{1+\frac{\sqrt2}{2}}

Simplify:                      \dfrac{\frac{\sqrt2}{2}}{\frac{2-\sqrt2}{2}}-\dfrac{\frac{\sqrt2}{2}}{\frac{2+\sqrt2}{2}}

                               =\dfrac{\sqrt2}{2-\sqrt2}-\dfrac{\sqrt2}{2+\sqrt2}

                               =\dfrac{\sqrt2}{2-\sqrt2}\bigg(\dfrac{2+\sqrt2}{2+\sqrt2}\bigg)-\dfrac{\sqrt2}{2+\sqrt2}\bigg(\dfrac{2-\sqrt2}{2-\sqrt2}\bigg)

                               =\dfrac{2\sqrt2+2}{4-2}-\dfrac{2\sqrt2-2}{4-2}

                               =\dfrac{4}{2}

                               = 2

LHS = RHS:  2 = 2  \checkmark

7 0
4 years ago
The ratio 5:15 simplifies to​
hram777 [196]

Answer:

5:15 simplifies to 1:3.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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