All categories

3 years ago

5. One of the attractions at Typhoon Lagoon, a water park in Florida, is a surf

Physics

1 answer:

tino4ka555 [31]3 years ago

3 0

Answer:

1595790 gallons

Explanation:

Given that;

3.8 L = 1 US gallon

303,200.0 liters = 303,200.0 * 1/ 3.8 = 79789.5 gallons

If a wave is made every 90 seconds which is 1.5 mins

Then;

Number of waves made in 30 minutes = 30/1.5 = 20 waves

if each uses 79789.5 gallons, then 20 waves will use 20 * 79789.5 gallons = 1595790 gallons

You might be interested in

. If measurements of a gas are 75L and 300 kilopascals and then the gas is measured a second time and found to be 50L, describe

julia-pushkina [17]

By Boyle's law:

P₁V₁ = P₂V₂

300*75 = P₂*50

P₂*50= 300*75

P₂ = 300*75/50 = 450

P₂ = 450 kiloPascals.

The pressure has increased as a result of compression of gas.

Boyle's Law supports this observation.

3 0

3 years ago

Read 2 more answers

Car a with mass 1,783 kg collides with stationary 1600 kg car b. they become locked together after the collision and move with s

ValentinkaMS [17]

The initial speed of car A is 15.18 m/s.

Momentum is defined as mass in motion. If there are two objects (the two objects in motion or only one object in motion and the other in stationary) that collide and no other forces work in the system, the law of momentum conservation applies in the system.

p=p'

pa+pb = pa'+pb'

(ma×va) + (mb×vb) = (ma×va') + (mb×vb')

ma = mass of object A (kg) = 1,783 kg
mb = mass of object B (kg) = 1,600 kg
va = speed of object A before collides (m/s)
va' = speed of object A after collides (m/s) = 8 m/s
vb = speed of object B before collides (m/s) = 0 m/s
vb' = speed of object B after collides (m/s) = 8 m/s
p = momentum before collision (Ns)
p' = momentum after collision (Ns)

(ma×va) + (mb×vb) = (ma×va') + (mb×vb')

(1,783×va) + (1,600×0) = (1,783×8) + (1,600×8)

(1,783×va) + 0 = 14,264+12,800

(1,783×va) = 27,064

$va \:=\: \frac{27,064}{1.783}$

va = 15.18 m/s

Learn more about The law of momentum conservation here: brainly.com/question/7538238

#SPJ4

3 0

1 year ago

Using Figure 2, what is the momentum of Train Car A before the collision?

Bess [88]

Answer:

Option A. 180000 Kgm/s.

Explanation:

From the question given above, the following data were obtained:

For Train Car A:

Mass of train car A = 45000 Kg

Velocity of train car A = 4 m/s

Momentum of train car A =?

For Train Car B:

Mass of train car B = 45000 Kg

Velocity of train car B = 0 m/s

Momentum is simply defined as the product of mass and velocity. Mathematically, it can be expressed as:

Momentum = mass × velocity

With the above formula, the momentum of train car A before collision can be obtained as follow:

Mass of train car A = 45000 Kg

Velocity of train car A = 4 m/s

Momentum of train car A =?

Momentum = mass × velocity

Momentum = 45000 × 4

Momentum of train car A = 180000 Kgm/s

5 0

3 years ago

The number of times a machine multiplies the effort force is the

____ [38]

Mechanical advantage

3 0

3 years ago

Which of the following best describes a chemical equation that demonstrates the law of conservation of matter?

LiRa [457]

B, since it is the only one that actually conserves matter for certain. In each of the others, matter could still be imbalanced, since for A, for example, it could be 5 Carbons on the right and 5 Chlorines on the left, and that would not balance.

3 0

3 years ago