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Cerrena [4.2K]
2 years ago
11

Can anyone say this is from which book And can you solve these question

Physics
1 answer:
babunello [35]2 years ago
5 0
You got a F on this assignment bro I’m telling you
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How do I solve this step by step? I’m really confused
LekaFEV [45]

Step-#1:

Ignore the wire on the right.

Find the strength and direction of the magnetic field at P,

caused by the wire on the left, 0.04m away, carrying 5.0A

of current upward.

Write it down.


Step #2:

Now, ignore the wire on the left.

Find the strength and direction of the magnetic field at P,

caused by the wire on the right, 0.04m away, carrying 8.0A

of current downward.

Write it down.


Step #3:

Take the two sets of magnitude and direction that you wrote down

and ADD them.


The total magnetic field at P is the SUM of (the field due to the left wire)

PLUS (the field due to the right wire).


So just calculate them separately, then addum up.

4 0
3 years ago
Which energy transformation occurs when an electrolytic cell is in operation.
hodyreva [135]

Answer:

An electrolytic cell converts electrical energy into chemical energy.

Explanation:

7 0
2 years ago
Suppose a certain jet plane creates an intensity level of 124 dB at a distance of 5.01 m. What intensity level does it create on
Zolol [24]

Answer:71 dB

Explanation:

Given

sound Level \beta _1=124 dB

distance r_1=5.01 m

From sound Intensity

\beta =10dB\log (\frac{I_1}{I_0})

124=10dB\log (\frac{I_1}{I_0})

12.4=\log (\frac{I_1}{I_0})

I_1=(1\times 10^{-12})\times 10^{12.4}

I_1=2.51 W/m^2

we know Intensity I\propto ^\frac{1}{r^2}

I_1r_1^2=I_2r_2^2

I_2=I_1(\frac{r_1}{r_2})^2

I_2=2.51\cdot (\frac{5.01}{2.25\times 10^3})^2

I_2=1.24\times 10^{-5} W/m^2

Sound level corresponding to I_2

\beta _2=10\log (\frac{I_2}{I_0})

\beta _2=10\log (\frac{1.24\times 10^{-5}}{1\times 10^{-12}})

\beta _2=70.93\approx 71 dB

6 0
3 years ago
when the driver of a car applies the brakes a force of 4000N brings the car to a stop over a distance of 50m.calculate the work
Dimas [21]

Answer:

W = F*d

W = 4000*50

W = 200000J

W = 200KJ

4 0
3 years ago
A lamp in a child's Halloween costume flashes based on an RC discharge of a capacitor through its resistance. The effective dura
Genrish500 [490]

Power of the lamp = (voltage) x (current)

0.62 watt = (3.0 v) x (current)

Current = (0.62 watt) / (3.0 volt)

Current = 0.207 Ampere

Charge = (current) x (time)

Charge = (0.207 Amp) x (0.32 sec)

<em>a).  Charge = 0.066 Coulomb</em>

Energy discharge through the lamp = (charge) x (voltage)

Energy = (0.66 C) x (3.0 volt)

Energy = 0.1984 Joule

Energy stored in a capacitor = (1/2) (Capacitance) (voltage²)

0.1984 Joule = (1/2) (Cap) (3.0 v)²

Cap = 2 x 0.1984 / 9

<em>b).  Cap = 0.044 Farad</em> (yikes !)

Resistance of the lamo = (voltage) / (current)

Resistance = (3.0 volt) / (0.207 Amp)

<em>c).  Resistance = 14.49 Ω</em>

All of this feels OK except for that ridiculous 44,000 μF, 3v capacitor.  Sadly, I have checked my work without finding an error, and I am too lazy to check it again.  So I'll call this my final answer, and leave it to some better Brainly person to find where I went wrong.

6 0
3 years ago
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