Can two objects exert a force on each other without touching? example

One hundred turns of (insulated) copper wire are wrapped around a wooden cylindrical core of cross-sectional area 1.32 × 10-3 m2

kenny6666 [7]

Answer:

The charge flos through the coil is 0.023C

Explanation:

To solve this problem, it is necessary to apply the concepts related to Faraday's Law in which it is possible to calculate the emf Voltage induced due to a charge in a magnetic field

and Ohm's Law for the calculation of the current based on a given load over time.

Our data are given by:

$N=100$

$A= 1.32*10^{-3}m^2$

$R=15\Omega$

Where

N is the number of loops, A the area and R the Resistance.

The change in magnetic field can be calculated as,

$dB = 1.31-(-1.31)$

$dB = 2.62T$

The Faraday's law of electromagnetic induction is given by definition as,

$V = NA \frac{dB}{dt}$

In the other hand Ohm's law says:

$V = IR$

$V = \frac{dq}{dt} R$

Equating both equations we have

$\frac{dq}{dt} R = NA \frac{dB}{dt}$

We can re-arrange the equations to solve q, then

$dq = \frac{NA(dB)}{R}$

$q = \frac{(100)(1.32*10^{-3})(2.62)}{15}$

$q = 0.023C$

Therefore the charge flos through the coil is 0.023C

8 0

3 years ago

A ball is dropped out of a window and hits the ground at 14.5 m/s. How long did it take to fall to the ground?

Lerok [7]

Answer:

Explanation:

Use the one-dimensional equation:

$v_f=v_0+at$ which says that the final velocity of a falling object is equal to its initial velocity times the acceleration of gravity times the time it takes to fall. We have the final velocity, -14.5 (negative because its direction is down and down is negative), initial velocity is 0 (because it was held still by someone before it was dropped), and acceleration is -9.8 (negative again, because direction is down while acceleration increases). Filling in:

-14.5 = 0 - 9.8t and

-14.5 = -9.8t so

t = 1.5 seconds

3 0

3 years ago

Heights of men on a baseball team have a bell-shaped distribution with a mean of 166 cm 166 cm and a standard deviation of 5 cm

kaheart [24]

Answer:

95 %

99.7 %

Explanation:

$\mu$ = 166 cm = Mean

$\sigma$ = 5 cm = Standard deviation

a) 156 cm and 176 cm

$166-5\times 2=156$

$166+5\times 2=176$

From the empirical rule 95% of all values are within 2 standard deviation of the mean, so about 95% of men are between 156 cm and 176 cm.

b) 151 cm and 181 cm

$166-5\times 3 =151$

$166+5\times 3=181$

The empirical rule tells us that about 99.7% of all values are within 3 standard deviations of the mean, so about 99.7% of men are between 151 cm and 181 cm.

3 0

3 years ago

An object is 50 cm from a converging lens with a focal length of 40 cm . A real image is formed on the other side of the lens, 2

Leno4ka [110]

Answer:

d) -4.0

Explanation:

The magnification of a lens is given by

$M=-\frac{q}{p}$

where

M is the magnification

q is the distance of the image from the lens

p is the distance of the object from the lens

In this problem, we have

p = 50 cm is the distance of the object from the lens

q = 250 cm - 50 cm is the distance of the image from the lens (because the image is 250 cm from the obejct

Also, q is positive since the image is real

So, the magnification is

$M=-\frac{200 cm}{50 cm}=-4.0$

7 0

3 years ago

The current through a circuit is 0.05 Amps. How many Coulombs of charge pass

Mazyrski [523]

The answer to this question is:

Simply it can be calculate using the equation Q=It, here Q is the charge in coulombs , I current in Amps and t is the time in seconds.

so the answer is Q = 10*60 = 600 coulomb.

5 0

3 years ago