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otez555 [7]
3 years ago
13

What is the area of rhombus ABCD? do not round any steps

Mathematics
1 answer:
katrin2010 [14]3 years ago
3 0
Because ABCD is a rhombus, ΔABC ~ ΔADC.

The length of AC = 4 (the base of ΔABC.
The height of ΔABC = 7 - 1 = 6
The area of ΔABC is
(1/2)*4*6 = 12

Therefore the area of ABCD = 2*12 = 24

Answer: 24

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If c = 4 and d = 5, find c:d.<br><br> 1:5<br> 4:5<br> 5:4
nadya68 [22]
The answer would be the second choice. 4:5
5 0
3 years ago
Read 2 more answers
How much of earth's surface is covered by water,including both salt and fresh water?
Crank

Answer:

About 71% of Earth's surface is covered in water.

Step-by-step explanation:

About 97% of Earth's water is salt water.

About 3% of Earth's water is fresh water.

7 0
3 years ago
Find the area of the trapezoid. points are (-5,-3)(4,-3)(6,-7)(-7,-7)​
Olegator [25]

Answer:

44 square units

Step-by-step explanation:

The area of a trapezoid with bases b₁ and b₂ and height h is given by the formula

A=\left(\dfrac{b_1+b_2}{2}\right)h

If you're wondering how we get this formula, check the attached illustration (remember the area of a parallelogram is its base multiplied by its height)! Moving on to our trapezoid, the pairs of points (-5,-3)(4,-3) and (6,-7)(-7,-7) form two horizontal segments, which form b₁ and b₂, and our height is the distance between the y-coordinates -3 and -7, which is 4. We can find b₁ and b₂ by finding the distance between the x coordinates in their pairs of points:

b_1=|-5-4|=|-9|=9\\b_2=|6-(-7)|=|6+7|=13

Putting it altogether:

A=\left(\dfrac{9+13}{2}\right)(4)=\left(\dfrac{22}{2}\right)(4)=(11)(4)=44

So the area of our trapezoid is 44.

4 0
3 years ago
What is the value of v? Please provide an explanation, thanks!
san4es73 [151]

Answer:

13

Step-by-step explanation:

(180-(11v+15)+9v-8+6v-9=180

4v+148=180

4v=52

v=52/4

=13°

7 0
2 years ago
Use the discriminant to determine how many solutions are possible for the following equation?(show work)
Gwar [14]

Answer:

see the explanation

Step-by-step explanation:

<u><em>The correct question is</em></u>

Use the discriminant to determine how many solutions are possible for the following equation (show  work).

5x^2-3x+4=0

we know that

The discriminant for a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

D=b^2-4ac

If D=0 then the equation has only one real solution

If D>0 then the equation has two real solutions

If D<0 then the equation has no real solutions (two complex solutions)

in this problem we have

5x^{2} -3x+4=0  

so

a=5\\b=-3\\c=4

substitute

D=-3^2-4(5)(4)

D=-71

so

The equation has no real solutions, The equation has two complex solutions

therefore

I know there are___No____

real solutions to the equation in problem 4 because  ___the discriminant is negative___

3 0
3 years ago
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