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otez555 [7]
3 years ago
13

What is the area of rhombus ABCD? do not round any steps

Mathematics
1 answer:
katrin2010 [14]3 years ago
3 0
Because ABCD is a rhombus, ΔABC ~ ΔADC.

The length of AC = 4 (the base of ΔABC.
The height of ΔABC = 7 - 1 = 6
The area of ΔABC is
(1/2)*4*6 = 12

Therefore the area of ABCD = 2*12 = 24

Answer: 24

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Kryger [21]
Hello! And thank you for your question!

First we are going to redo the equation:

<span><span><span>y<span><span>​^3</span><span>​​</span></span></span>−3<span>y^<span><span>​2</span><span>​​</span></span></span>(3)+3(y)×<span>3<span><span>​^2</span><span>​​</span></span></span>−<span>3<span><span>​^3</span><span>​​</span></span></span>=0

Then we are going to use Cube of Difference:

0 = (y - 3)^3

That take cube root of both sides:

0 = y - 3

Finally add 3 to both sides:

3 = y

Final Answer:

y = 3</span></span>
4 0
3 years ago
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Galina-37 [17]

Answer:

1. C

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3. B

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Step-by-step explanation:

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Stels [109]

Answer:

e : g = 2 : 7

Step-by-step explanation:

e/f = 3/7

e = 3f/7

f/g = 2/3

g = 3f/2

e/g = (3f/7)/(3f/2) = 2/7

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postnew [5]

Answer?

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katrin [286]

Answer:

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Step-by-step explanation:

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