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ch4aika [34]
3 years ago
6

A 5.0-gram sample of Fe(s) is to be placed in 100. milliliters of HCl(aq). Which changes will result in the fastest rate of reac

tion?
Chemistry
1 answer:
guajiro [1.7K]3 years ago
8 0
<span>Raising the temperature of the reactants increases the reaction between the reactants. The kinetic energy of the molecules of the reactants collides more frequently with ach other thereby increasing its reaction. Increasing the concentration of the reactants increases the reaction rate. Adding a catalyst to the reaction increases the rate of reaction of a substance. The catalyst hastens the chemical reaction. </span>
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What is the relationship between the number of each atom used to form compound and oxidation number?
deff fn [24]

Answer:Explanation:

In compounds, all other atoms are assigned an oxidation number so that the sum of the oxidation numbers on all the atoms in the species equals the charge on the species.

6 0
3 years ago
Plz help i’m stuckkkk
scZoUnD [109]

Answer:

first

Explanation:

Assets = Equity + Liability. ...

Assets = Liabilities + Shareholder's Equity.

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3 0
3 years ago
The reaction C 4 H 8 ( g ) ⟶ 2 C 2 H 4 ( g ) C4H8(g)⟶2C2H4(g) has an activation energy of 262 kJ / mol. 262 kJ/mol. At 600.0 K,
ludmilkaskok [199]

Answer: 4.3\times 10^{-13}s^{-1}

Explanation:

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

or,

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = rate constant at 600.0K = 6.1\times 10^{-8}s^{-1}

K_2 = rate constant at 775.0 = ?

Ea = activation energy for the reaction = 262 kJ/mol = 262000J/mol

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 600.0K

T_2 = final temperature = 775.0K

Now put all the given values in this formula, we get

\log (\frac{6.1\times 10^{-8}}{K_2})=\frac{262000}{2.303\times 8.314J/mole.K}[\frac{1}{600.0K}-\frac{1}{775.0K}]

\log (\frac{6.1\times 10^{-8}s^}{K_2})=5.150

(\frac{6.1\times 10^{-8}}{K_2})=141253.8

Therefore, the value of the rate constant at 775.0 K is 4.3\times 10^{-13}s^{-1}

5 0
3 years ago
What aqueous solution has the highest boiling point at standard pressure? A) 1.0 M KCl(aq) B) 1.0 M CaCl2(aq) C) 2.0 M KCl(aq) D
Lapatulllka [165]
The increase in the boiling point of a solvent is a colligative property.


That means that the increase in the boling point will be related to the number of particles (molecules or ions) present in the solution.


The higher the number of particles (molecules or ions) the higher the increase in the boiling point.


All the aqueous solutions presented are electrolytes, i.e. the solutes are ionic compounds.


Then, you have to compare the number of ions that you have in each solution.


A) 1.0 M KCl ---> 1.0 M K+     +      1.0 MCl-    = 2 moles of particles / liter


B) 1.0 M CaCl2 --> 1.0M Ca(2+)      +      1.0M * 2 Cl (-)    = 3 moles of particle / liter


C) 2.0M KCl ---> 2.0 M K+      +      2.0 M Cl-  = 4 moles of particle / liter


D) 2.0 M CaCl2 ----> 2.0 M Ca (2+)      + 2.0M * 2 Cl (-)  = 6 moles of particle / liter.


Then, the solution 2.0M CaCl2(aq) has the highest increase in the boiling point.


Answer: option D) 2.0 M Ca Cl2(aq)
5 0
3 years ago
Can someone show me a step by step with the answer?
Georgia [21]

Answer:

6 mols HCl

Explanation:

(I'm an AP chemistry student but not perfect at this stuff)

you can use the Molarity=Moles/L equation here:

(6M)=(moles HCl)/(1L)

divide by 1 on both sides to isolate the moles of HCl

this gets you 6 moles HCl.

Again I'm just a student so my answer might be wrong, but this question should just require the M=mols/L equation :).

8 0
3 years ago
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