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ch4aika [34]
3 years ago
6

A 5.0-gram sample of Fe(s) is to be placed in 100. milliliters of HCl(aq). Which changes will result in the fastest rate of reac

tion?
Chemistry
1 answer:
guajiro [1.7K]3 years ago
8 0
<span>Raising the temperature of the reactants increases the reaction between the reactants. The kinetic energy of the molecules of the reactants collides more frequently with ach other thereby increasing its reaction. Increasing the concentration of the reactants increases the reaction rate. Adding a catalyst to the reaction increases the rate of reaction of a substance. The catalyst hastens the chemical reaction. </span>
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If D+2 would react with E-1, what do you predict the formula to be. A) DE B)D2E C)DE2 D) D2E2
allochka39001 [22]
All you need to do the cross the charges and put it as suffixes. 

D+2 + E-1 ----> DE2

answer is C
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The products are favored over the reactants
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Glycolic acid, which is a monoprotic acid and a constituent in sugar cane, has a pKa of 3.9. A 25.0 mL solution of glycolic acid
Phoenix [80]

Answer:

pH = 8.0

Explanation:

First, we have to calculate the moles of NaOH.

35.8 \times 10^{-3}L.\frac{0.020mol}{L} =7.2\times 10^{-4}mol

Let's consider the balanced equation.

C₂H₄O₃ + NaOH ⇒ C₂H₃O₃Na + H₂O

The molar ratio C₂H₄O₃: NaOH: C₂H₃O₃Na is 1: 1: 1. So, when 7.2 × 10⁻⁴ moles of NaOH react completely with 7.2 × 10⁻⁴ moles of C₂H₄O₃ they form 7.2 × 10⁻⁴ moles of C₂H₃O₃Na.

The concentration of C₂H₃O₃Na is:

\frac{7.2\times 10^{-4}mol}{60.8 \times 10^{-3}L} =0.012M

C₂H₃O₃Na dissociates according to the following equation:

C₂H₃O₃Na(aq) ⇒ C₂H₃O₃⁻(aq) + Na⁺(aq)

C₂H₃O₃⁻ comes from a weak acid so it undergoes basic hydrolisis.

C₂H₃O₃⁻ + H₂O ⇄ C₂H₄O₃ + OH⁻

If we know that pKa for C₂H₄O₃ is 3.9, we can calculate pKb for C₂H₃O₃⁻ using the following expression:

pKa + pKb = 14

pKb = 14 -3.9 = 10.1

10.1 = -log Kb

Kb = 7.9 × 10⁻¹¹

We can calculate [OH⁻] using the following expression:

[OH⁻] = √(Kb.Cb)               <em>where Cb is the initial concentration of the base</em>

[OH⁻] = √(7.9 × 10⁻¹¹ × 0.012M) = 9.7 × 10⁻⁷ M

Now, we can calculate pOH and pH.

pOH = -log [OH⁻] = -log (9.7 × 10⁻⁷) = 6.0

pH + pOH = 14

pH = 14 - pOH = 14 - 6.0 = 8.0

7 0
3 years ago
Explain how an element that does not react easily with other elements can be useful.
BaLLatris [955]
Elements that are unreactive can be useful for 'isolating' other volatile elements. For example, an element may be highly reactive with oxygen, so keeping it in air is not a safe option. In such cases, it may be useful to have a noble gas to store the element safely and ensure its stability. It may also have a purpose in experiments where it may act as a controlling agent or a container for the other reactions. 
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4 years ago
Which is the electronic configuration for oxygen?
hjlf
8O

the electron configuration for oxygen is 1s2 2s2 2p4
6 0
3 years ago
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