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MrRa [10]
3 years ago
8

How many O atoms are in 4C₆H₁₂O₆

Chemistry
1 answer:
ipn [44]3 years ago
6 0

Number of O atoms : 24

<h3>Further explanation</h3>

Given

C₆H₁₂O₆ compound

Required

Number of atoms

Solution

A molecular formula  shows the number of atomic elements in compound.  

The empirical formula is the smallest comparison of the atoms

Glucose-C₆H₁₂O₆ is composed of 3 elements, namely C, H, and O.

The number of atoms in a compound can usually be seen from the subscript number after the atom and the reaction coefficient shows the number of molecules

So number of O atoms :

= 4 x 6 = 24 atoms

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We have been given with atomic masses for ^1^5^1_E_u and ^1^5^3_E_u as 150.919860 and 152.921243 amu, respectively.  Average atomic mass of Eu is 151.964 amu.

Sum of natural abundances of isotopes of an element is always 1. If we assume the abundance of ^1^5^1_E_u as n then the abundance of ^1^5^3_E_u would be 1-n .

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151.964=150.919860(n)+152.921243(1-n)

151.964=150.919860n+152.921243-152.921243n

on keeping similar terms on same side:

151.964-152.921243=150.919860n-152.921243n

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0.957243=2.001383n

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= 0.522 which is 52.2%

Hence, the natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .


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