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liberstina [14]
3 years ago
9

Balancing Chemical Equations & Identifying Chemical Reactions

Chemistry
1 answer:
Stells [14]3 years ago
3 0
The answer is 17 and a half
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Give the major force between acetone and chloroform.
EleoNora [17]
Says here the answer is <span>dipole-dipole</span>
4 0
3 years ago
Which of the following shows the correct path of blood through the heart and lungs?
jeyben [28]

Answer:

B

Explanation:

Always remember blood first flows from atria (remember A comes before V) to ventricles and the right side always carries deoxgenated blood to the lungs which then arrives through the left side when oxygenated

5 0
2 years ago
Read 2 more answers
A student has two unopened 33 CL cans containing carbonated water. Can A has been stored in the garage 32 degrees and can B has
IgorC [24]

Answer:

A. Can A will make a louder and stronger fizz than can B.  

Explanation:

The solubility of a gas in a liquid decreases as the temperature increases, so the warmer can will have more undissolved carbon dioxide.

The warmer can will be under greater pressure, so it will make a louder and stronger fizz.

7 0
3 years ago
If 3.53 g of CuNO, is dissolved in water to make a 0.330 M solution, what is the volume of the solution in milliliters?
solmaris [256]

Answer:

84.8 mL

Explanation:

From the question given above, the following data were obtained:

Mass of CuNO₃ = 3.53 g

Molarity of CuNO₃ = 0.330 M

Volume of solution =?

Next, we shall determine the number of mole in 3.53 g of CuNO₃. This can be obtained as follow:

Mass of CuNO₃ = 3.53 g

Molar mass of CuNO₃ = 63.5 + 14 + (16×3)

= 63.5 + 14 + 48

= 125.5 g/mol

Mole of CuNO₃ =?

Mole = mass / Molar mass

Mole of CuNO₃ = 3.53 / 125.5

Mole of CuNO₃ = 0.028 moles

Next, we shall determine the volume of the solution. This can be obtained as follow:

Molarity of CuNO₃ = 0.330 M

Mole of CuNO₃ = 0.028 moles

Volume of solution =?

Molarity = mole /Volume

0.330 = 0.028 / Volume

Cross multiply

0.330 × Volume = 0.028

Divide both side by 0.330

Volume = 0.028 / 0.330

Volume = 0.0848 L

Finally, we shall convert 0.0848 L to millilitres (mL). This can be obtained as follow:

1 L = 1000 mL

Therefore,

0.0848 L = 0.0848 L × 1000 mL / 1 L

0.0848 L = 84.8 mL

Therefore, the volume of the solution is 84.8 mL.

8 0
2 years ago
What is the temperature difference if 300 cal are used to warm water
PIT_PIT [208]

Answer:

<u>The temperature difference is</u> \frac{300}{m} Kkg^{-1}

Explanation:

The formula that is to used is :

ΔQ=msΔT

<em>where ,</em>

  • <em>ΔQ is the heat supplied in calories = 300cal</em>
  • <em>m is the mass of water taken = m (assumed)</em>
  • <em>ΔT is the change in temperature</em>
  • <em>s is the specific heat of water = 1calK^{-1}Kg^{-1}</em>

ΔT :

\frac{300}{m*1} \\=\frac{300}{m} Kkg^{-1}

6 0
3 years ago
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