PLEASE HELP ME FOR EXTRA POINTS AND BRAINLIEST ANWSER

On a very hot summer day, 5% of the production employees at Midland States Steel are absent from work. The production employees

Ann [662]

Answer:

59.87% probability of randomly selecting 10 production employees on a hot summer day and finding that none of them are absent

Step-by-step explanation:

For each employee, there are only two possible outcomes. Either they are absent, or they are not. The probability of an employee being absent is independent from other employees. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

5% of the production employees at Midland States Steel are absent from work.

This means that $p = 0.05$

What is the probability of randomly selecting 10 production employees on a hot summer day and finding that none of them are absent

This is P(X = 0) when n = 10. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.05)^{0}.(0.95)^{10} = 0.5987$

59.87% probability of randomly selecting 10 production employees on a hot summer day and finding that none of them are absent

4 0

3 years ago

The Hickory Stick has a selection of 3 meats and 6 vegetables. How many different selections of one meat and one vegetable are p

valentina_108 [34]

The different selections of one meat and one vegetable are possible are 18 selections.

Since the Hickory Stick has a selection of 3 meats and 6 vegetables, the number of ways we can select one meat out of 3 is ³C₁ = 3.

Also, the number of ways we can select one vegetable out of 6 is ⁶C₁ = 6.

So, the total number of selections of one meat and one vegetable is ³C₁ × ⁶C₁ = 3 × 6

= 18 selections

So, the different selections of one meat and one vegetable are possible are 18 selections.

Learn more about combination here:

brainly.com/question/19341024

7 0

2 years ago

Part B Isabella's mother sells the peas and gets $3 for each square foot. So, multiply your answer from Part A by 3 to calculate

choli [55]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete as the solution to part A (or part A itself) is not given. To solve this, I will assume a value to the supposes solution to part A.

From the question:

1 square foot is sold at $3.

This implies that:

p square foot will be sold at $3p.

So, total sales can be calculated using:

$Total = 3p$

Now assume that p is 10 square feet (from part A).

The total will be:

$Total = 3*10$

$Total = \$30$

4 0

3 years ago

If eggs cost $3 per dozen. how much would 8 eggs cost?

weeeeeb [17]

12 eggs = $3
8 eggs = (8÷12) × $3

hope this was helpful! :)

3 0

4 years ago

Read 2 more answers

Vugar has a maximum of 30 batteries for toys. Each toy helicopter uses the same number of batteries, and each toy car uses the s

Leno4ka [110]

Answer: 3H+4C<_ 30

The coefficients of the variables H and C represent the number of batteries each toy helicopter and each toy car uses.

Step-by-step explanation:

Each toy helicopter uses 3 batteries, and each toy car uses 4 batteries.

Now let's check whether Vugar has enough batteries for 5 toy helicopters and 4 toy cars. To do this, we substitute H=5 and C= 4 in the given inequality:

Does Vugar have enough batteries to play with 5 toy helicopters and 4 toy cars?

No, because if you plug in the value for H and C:

3H + 4C<_ 30

3(5) + 4(4) <_30

15 + 16 <_ 30

31 <_ 30; false

Since the inequality is false, Vugar does not have enough batteries to play with 555 toy helicopters and 444 toy cars.

Each toy helicopter uses 333 batteries, and each toy car uses 444 batteries.

No, Vugar does not have enough batteries to play with 555 toy helicopters and 444 toy cars.

6 0

4 years ago

Read 2 more answers