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Anit [1.1K]
3 years ago
12

Calculate the atomic mass of nitrogen if the two common isotopes of

Chemistry
1 answer:
Misha Larkins [42]3 years ago
3 0

Answer:

Atomic mass of nitrogen = 14.0067 amu.

Explanation:

Isotopes can be defined as two or more forms of a chemical element that are made up of equal numbers of protons and electrons but different numbers of neutrons.

Generally, the isotopes of a chemical element have the same chemical properties because of their atomic number but different physical properties due to their atomic weight (mass number).

The two isotopes of nitrogen are nitrogen-14 and nitrogen-15.

Given the following data;

Relative abundance of N-14 = 99.63%

Atomic mass of N-14 = 14.003

Relative abundance of N-15 = 0.37%

Atomic mass of N-15 = 15.000

The atomic mass is;

14.003 × (99.63/100) + 15.000 × (0.37/100)

Atomic mass = 14.003 × (0.9963) + 15.000 × (0.0037)

Atomic mass = 13.9512 + 0.0555

Atomic mass = 14.0067 amu.

<em>Therefore, the atomic mass of nitrogen is 14.0067 amu. </em>

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How many grams of ammonia produced from 1000 grams of N2?
sleet_krkn [62]

Answer:

N2 + 3H2 ———> 2NH3

As we know 1000 grams ammonia is 58.82 moles so according to unitary method,

2 mole NH3 formed by 1 mole N2 hence 58.82 NH3 will be given by 29.41 moles N2.

No. Of moles = given mass/molar mass

Implies that

Mass of nitrogen required = 29.41*28 = 823.48 grams.

Explanation:

5 0
2 years ago
Which of the following is true for a chemical reaction at equilibrium?
victus00 [196]

Answer:

youre gonna have to include the answers for me to help

Explanation:

7 0
2 years ago
1.12g H2 is allowed to react with 9.60 g N2, producing 1.23 g NH3.
andriy [413]

Answer:

A. m_{NH_3}^{theo} =1.50gNH_3

B. Y=82.2\%

Explanation:

Hello!

In this case, since the undergoing chemical reaction between nitrogen and hydrogen is:

N_2+3H_2\rightarrow 2NH_3

Thus we proceed as follows:

A. Here, we first need to compute the moles of ammonia yielded by each reactant, in order to identify the limiting one:

n_{NH_3}^{by \ H_2}=1.12gH_2*\frac{1molH_2}{2.02gH_2}*\frac{2molNH_3}{3molH_2}=0.370molNH_3\\\\  n_{NH_3}^{by \ N_2}=1.23gN_2*\frac{1molN_2}{28.02gN_2}*\frac{2molNH_3}{1molN_2}=0.0878molNH_3

Thus, since nitrogen yields the fewest moles of ammonia, we realize it is the limiting reactant, so the theoretical yield, in grams, of ammonia is:

m_{NH_3}^{theo}=0.0878mol*\frac{17.04gNH_3}{1molNH_3} =1.50gNH_3

B. Finally, since the actual yield of ammonia is 1.23, the percent yield turns out:

Y=\frac{1.23gNH_3}{1.50gNH_3} *100\%\\\\Y=82.2\%

Best regards!

5 0
3 years ago
Sodium electron configuration in longhand notation
Elden [556K]

Answer:

Na₁₁ = 1s² 2s² 2p⁶ 3s¹

Explanation:

Sodium is present in group 1.

It is alkali metal.

It has one valence electron.

The atomic number of sodium is 11.

Its atomic mass is 23 amu.

The longhand notation of electronic configuration of sodium can be written as,

Na₁₁ = 1s² 2s² 2p⁶ 3s¹

The electronic configuration in shorthand notation( noble gas) would be written as,

Na₁₁ = [Ne] 3s¹

Sodium loses its one valence electron to complete the octet and get stable thus form +1 cation.

It react with halogen and form salt. Such as sodium chloride.

2Na + Cl₂  →  2NaCl

5 0
3 years ago
Which process requires water to gain heat energy from the environment
elixir [45]

Answer:

Evaporation

Explanation:

Evaporation is the certain process that requires water to gain heat energy from the environment.

4 0
3 years ago
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