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IgorC [24]
3 years ago
14

An acid (such as H2SO4) and a base (such as NaOH) are mixed together during a titration. The equivalence point is reached when _

____.
the pH reaches its maximum value

the number of moles of H+ ions equals the number of moles of OH– ions

the pH reaches its minimum value

the number of moles of acid equals the number of moles of base
Chemistry
2 answers:
dolphi86 [110]3 years ago
6 0
The answer is "<span>the number of moles of H+ ions equals the number of moles of OH– ions "</span>
raketka [301]3 years ago
4 0

Answer:

the number of moles of H+ ions equals the number of moles of OH– ions

Explanation:

The equivalence point, is the point at which the acid has completely reacted with the base.

In other words, the H+ ions from the acid have completed reacted with the OH- ions from the base, and in order to complete the reaction the moles of OH- must be equal to the number of moles of H+ in the inicial solution.

This is different to the moles of acid or base, because in this case we have two moles of H+ per mol of acid (H2SO4)

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An atomic radius is about 1.00*10^2 pm. Convert the radius to inches. (1 pm=10^-12m)
natka813 [3]

Answer:

3.937 x 10⁻⁸ inches

Explanation:

Data Given:

Atomic radium in pm (picometer) = 1.00 x 10² pm

Atomic radium in inches = ?

1 pm = 10⁻¹² m

Solution:

First convert picometer to meter

As we Know

  1 pm = 10⁻¹² m

then

  1.00 x 10² pm = X meter

Do cross multiplication

        X meter = (1.00 x 10² pm)(10⁻¹² m) / 1 pm

       X meter = 1 x 10⁻⁹ m

So, 1.00 x 10² pm equal to 1 x 10⁻⁹ m

Now convert meter to inches

As

         1 m = 39.37 inches

         1 x 10⁻⁹ m = X inches

Do cross multiplication

        X inches = (39.3701 inches)(1 x 10⁻⁹ m ) / 1 m

        X inches = 3.937 x 10⁻⁸ inches

So,

1.00 x 10² pm = 3.937 x 10⁻⁸ inches

so the radius is 3.937 x 10⁻⁸ inches

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