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IgorC [24]
3 years ago
14

An acid (such as H2SO4) and a base (such as NaOH) are mixed together during a titration. The equivalence point is reached when _

____.
the pH reaches its maximum value

the number of moles of H+ ions equals the number of moles of OH– ions

the pH reaches its minimum value

the number of moles of acid equals the number of moles of base
Chemistry
2 answers:
dolphi86 [110]3 years ago
6 0
The answer is "<span>the number of moles of H+ ions equals the number of moles of OH– ions "</span>
raketka [301]3 years ago
4 0

Answer:

the number of moles of H+ ions equals the number of moles of OH– ions

Explanation:

The equivalence point, is the point at which the acid has completely reacted with the base.

In other words, the H+ ions from the acid have completed reacted with the OH- ions from the base, and in order to complete the reaction the moles of OH- must be equal to the number of moles of H+ in the inicial solution.

This is different to the moles of acid or base, because in this case we have two moles of H+ per mol of acid (H2SO4)

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What is the main purpose of using NaOH in the saponification reaction . NaOH works as the catalyst b. NaOH solution is the solve
Alex777 [14]

Answer:

C. NaOH acts as a reactant in the reaction

Explanation:

Because during the saponification process, Na+ replaces the H+ in the fatty acid been used for the saponification process

7 0
4 years ago
Answer the following questions based on the reaction below: NaOH(aq) + KHP(s) --&gt; NaKP(aq)+H2O(I)
Natali [406]

Answer:

<u />

  • <u>a) 1.44g</u>

<u />

  • <u>b) 77.3%</u>

<u />

Explanation:

<u>1. Chemical balanced equation (given)</u>

       NaOH(aq)+ KHP(s)\rightarrow NaKP(aq)+H_2O(l)

<u>2. Mole ratio</u>

1molNaOH(aq):1molKHP(s)

This is, 1 mol of NaOH will reacts with 1 mol of KHP.

<u />

<u>3. Find the number of moles in 72.14 mL of the base</u>

    Molarity=\text{number of moles of solute}/\text{volume of solution in liters}

    \text{Volume of solution}=72.14mL=0.07214liters

     \text{Number of moles of NaOH}=0.0978M\times 0.07214liter=0.007055mol

<u>4. Find the number of grams of KHP that reacted</u>

The number of moles of KHP that reacted is equal to the number of moles of NaOH, 0.007055 mol

Convert moles to grams:

  • mass = number moles × molar mass = 0.007055mol × 204.23g/mol
  • mass = 1.4408 g.

You have to round to 3 significant figures: 1.44 g (because the molarity is given with 3 significant figures).

<u>5. Find the percentage of KHP in the sample</u>

The percentage is how much of the substance is in 100 parts of the sample.

The formula is:

  • % = (mass of substance / mass of sample) × 100

  • % = (1.4408g/ 1.864g) × 100 = 77.3%
7 0
3 years ago
Part A Find ΔS∘ for the reaction between nitrogen gas and hydrogen gas to form ammonia: 12N2(g)+32H2(g)→NH3(g) Express your answ
inessss [21]

Answer:

\Delta S^{0} for the given reaction is -99.4 J/K

Explanation:

Balanced reaction: \frac{1}{2}N_{2}(g)+\frac{3}{2}H_{2}(g)\rightarrow NH_{3}(g)

\Delta S^{0}=[1mol\times S^{0}(NH_{3})_{g}]-[\frac{1}{2}mol\times S^{0}(N_{2})_{g}]-[\frac{3}{2}mol\times S^{0}(H_{2})_{g}]

where S^{0} represents standard entropy.

Plug in all the standard entropy values from available literature in the above equation:

\Delta S^{0}=[1mol\times 192.45\frac{J}{mol.K}]-[\frac{1}{2}mol\times 191.61\frac{J}{mol.K}]-[\frac{3}{2}mol\times 130.684\frac{J}{mol.K}]=-99.4J/K

So, \Delta S^{0} for the given reaction is -99.4 J/K

7 0
4 years ago
Substance
ipn [44]

Answer:

lithium 3

Explanation:

This is because lithium has three protons

6 0
3 years ago
Which term describes the molecule shown below h-c-c-h ethyne c2h2?
Andru [333]
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4 0
3 years ago
Read 2 more answers
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