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nikklg [1K]
3 years ago
8

A sample of oxygen gas was collected via water displacement. since the oxygen was collected via water displacement, the sample i

s saturated with water vapor. if the total pressure of the mixture at 26.4 °c is 817 torr, what is the partial pressure of oxygen
Chemistry
1 answer:
NeX [460]3 years ago
3 0
Missing question: <span> The vapor pressure of water at 26.4 °C is 25.81 mm Hg.
p(total) = p(H</span>₂O) + p(O₂).
p(total) = 817 torr; <span> total pressure of the mixture.
</span>p(H₂O) = 25.81 torr, <span>partial pressure of water.
</span>p(O₂) = 817 torr - 25.81.
p(O₂) = 791.19 torr; partial pressure of oxygen.
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Particle size directly affects which of the following spil properties?
77julia77 [94]

Answer:

The size of soil particles is important. The amount of open space between the particles influences how easily water moves through a soil and how much water the soil will hold. Too much clay, in proportion to silt and sand, causes a soil to take in water very slowly. Such a soil gives up its water to plants slowly.

3 0
3 years ago
The equilibrium constant has been estimated to be 0.12 at 25 °C. If you had originally placed 0.069 mol of cyclohexane in a 2.8
scZoUnD [109]

Answer: Concentrations of cyclohexane and methylcyclopentane at equilibrium are 0.0223 M and 0.0027 M respectively

Explanation:

Moles of cyclohexane = 0.069 mole

Volume of solution = 2.8 L

Initial concentration of cyclohexane =\frac{moles}{Volume}=\frac{0.069}{2.8}=0.025M

The given balanced equilibrium reaction is,

                            cyclohexane  ⇔  methylcyclopentane

Initial conc.                 0.025 M           0

At eqm. conc.       (0.025-x)M       (x) M

The expression for equilibrium constant for this reaction will be,

K= methylcyclopentane / cyclohexane

Now put all the given values in this expression, we get :

0.12=\frac{(x)}{(0.025-x)}

By solving the term 'x', we get :

x =  0.0027

Concentration of cyclohexane at equilibrium = (0.025-x ) M = (0.025-0.0027) M = 0.0223 M

Concentration of methylcyclopentane at equilibrium = (x ) M = (0.0027) M

4 0
3 years ago
The critical point of carbon dioxide is 304 k and 73 atm. under which conditions is carbon dioxide a liquid? i. 303 k and 73 atm
Sergeeva-Olga [200]
Answer is: a) I only.
Above critical temperature of CO₂, a gas cannot be liquefied no matter how much pressure is applied. Temperature and pressure above its critical point is called supercritical fluid and this is <span>intermediate between gaseous and liquid states.</span>
7 0
3 years ago
How many molecules are in 41.8 g of sulfuric acid
Anton [14]

Answer

× 10²³ molecules are in 41.8 g of sulfuric acid

Explanation

The first step is to convert 41.8 g of sulfuric acid to moles by dividing the mass of sulfuric acid by its molar mass.

Molar mass of sulfuric acid, H₂SO₄ = 98.079 g/mol

Mole=\frac{Mass}{Molar\text{ }mass}=\frac{41.8\text{ }g}{98.079\text{ }g\text{/}mol}=0.426187053\text{ }mol

Finally, convert the moles of sulfuric acid to molecules using Avogadro's number.

Conversion factor: 1 mole of any substance = 6.022 × 10²³ molecules.

Therefore, 0.426187053 moles of sulfuric acid is equal

\frac{0.426187053\text{ }mol}{1\text{ }mol}\times6.022×10²³\text{ }molecules=2.57\times10^{23}\text{ }molecules

Thus, 2.57 × 10²³ molecules are in 41.8 g of sulfuric acid.

3 0
1 year ago
Which is a reactant in the cellular respiration reaction
Alexxandr [17]

Answer: Oxygen and glucose are both reactants in the process of cellular respiration.

Explanation: Oxygen and glucose are both reactants in the process of cellular respiration. The main product of cellular respiration is ATP; waste products include carbon dioxide and water.

7 0
3 years ago
Read 2 more answers
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