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Stella [2.4K]
3 years ago
15

A scuba diver that ascends to the surface too quickly can experience decompression sickness, which occurs when nitrogen that dis

solves in the blood under high pressure, forms bubbles as the pressure decreases during the ascent. Therefore, an understanding of the gas laws is an important part of a scuba diver's training. In fresh water, the pressure increases by 1 atm every 34 ft below the water surface a diver descends.
If a diver ascends quickly to the surface from a depth of 102 ft without exhaling, by what factor will the volume of the diver's lungs change upon arrival at the surface?
Chemistry
1 answer:
Butoxors [25]3 years ago
5 0

Answer:

The factor that will change the volume of the diver's lungs upon reaching the surface is 4

Explanation:

Given data:

Pressure increases 1 atm = 101.325 kPa

34 ft = 10.3632 m

Depth of 102 ft = 31.0896 m

Question: What factor will the volume of the diver's lungs change upon arrival at the surface, V₂/V₁ = ?

The pressure at 31.0896 m:

P_{1} =101.325+(\frac{31.0896}{10.3632} *101.325)=405.3kPa

The factor will the volume of the diver's lungs change upon arrival at the surface:

\frac{V_{2}}{V_{1} } =\frac{P_{1}}{P_{2}} =\frac{405.3}{101.325} =4

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1. The molar mass of the unknown gas obtained is 0.096 g/mol

2. The pressure of the oxygen gas in the tank is 1.524 atm

<h3>Graham's law of diffusion </h3>

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

<h3>1. How to determine the molar mass of the gas </h3>
  • Rate of unknown gas (R₁) = 11.1 mins
  • Rate of H₂ (R₂) = 2.42 mins
  • Molar mass of H₂ (M₂) = 2.02 g/mol
  • Molar mass of unknown gas (M₁) =?

R₁/R₂ = √(M₂/M₁)

11.1 / 2.42 = √(2.02 / M₁)

Square both side

(11.1 / 2.42)² = 2.02 / M₁

Cross multiply

(11.1 / 2.42)² × M₁ = 2.02

Divide both side by (11.1 / 2.42)²

M₁ = 2.02 / (11.1 / 2.42)²

M₁ = 0.096 g/mol

<h3>2. How to determine the pressure of O₂</h3>

From the question given above, the following data were obtained:

  • Volume (V) = 438 L
  • Mass of O₂ = 0.885 kg = 885 g
  • Molar mass of O₂ = 32 g/mol
  • Mole of of O₂ (n) = 885 / 32 = 27.65625 moles
  • Temperature (T) = 21 °C = 21 + 273 = 294 K
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Pressure (P) =?

The pressure of the gas can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

Divide both side by V

P = nRT / V

P = (27.65625 × 0.0821 × 294) / 438

P = 1.524 atm

Learn more about Graham's law of diffusion:

brainly.com/question/14004529

Learn more about ideal gas equation:

brainly.com/question/4147359

6 0
2 years ago
An astronaut leaves the International Space Station (ISS) on a tethered line. Although ISS and Earth exert gravitational force o
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Answer: D)The distance from Earth and mass of ISS exert negligible gravitational force on the astronaut.

Explanation:

The distance from Earth and mass of ISS exert negligible gravitational force on the astronaut. Gravity is a very weak force and varies with mass and the inverse square of distance. The astronaut's distance from Earth and the relative small mass of ISS result in gravitational force near zero.

8 0
2 years ago
The instructions for the experiment direct you to prepare 30 mL of 1.5 M HCl solution. In the chemical closet, you locate an 18M
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The volume of the 18M HCl needed to make the solution will be 2.5 mL.

<h3>Dilution</h3>

According to the dilution principle, the number of moles of solutes in a solution before and after dilution must remain the same.

Since, mole = molarity x volume

Thus, molarity x volume before dilution = molarity x volume after dilution.

Mathematically, the equation is written as: m1v1 = m2v2

In this case, m1 = 18 M, m2 = 1.5 M, and v2 = 30 mL.

What we are looking for is v1, the amount of the stock HCl needed for dilution.

v1 = m2v2/m1 = 1.5 x 30/18 = 2.5 mL.

Thus, 2.5 mL of the stock HCl would be needed.

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6 0
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WILL GIVE BRAINLIEST!!!
Hoochie [10]
Hey there!:

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number of moles glucose:

n = mass of solute / molar mass

n = 21.5 / 180

n = 0.119 moles glucose

Amount of solvent in kg = 255/1000 = 0.255 Kg

Molality = number of moles / solvent

m = 0.119 / 0.255

m = 0.466 moles/kg

Kf for water = - 1.86 ºC/*m

Therefore:

ΔTf = Kf * m

ΔTf = (-1,86) * 0.466

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