Answer:
See Explanation
Explanation:
An electrolyte is a solution which is able to conduct electricity. An electrolyte conducts electricity because of the presence of ions which move around in the solution.
Ba(OH)2 and H2SO4 are composed of ions; these ions are the charge carriers in solution and are responsible for the conductivity of the solution and the glow of the bulb.
When Ba(OH)2 and H2SO4 are mixed, the following reaction occurs;
Ba(OH)2(aq) + H2SO4(aq) -------->BaSO4(s) + 2H2O(l)
The formation of the BaSO4(s) precipitate removes the ions that are responsible for the conductivity of the solution hence the light bulb of the conductivity apparatus dims and eventually fades completely.
Answer:
19.5g is the theoretical yield of alum
Explanation:
Based on the balanced reaction, 4 moles of sulfuric acid produce 2 moles of alum. To solve this question we need to find the moles of H2SO4. With these moles we can find the moles of alum and its mass assuming all sulfuric acid reacts producing alum.
<em>Moles Sulfuric Acid:</em>
8.3mL = 0.0083L * (9.9mol/L) = 0.08217 moles sulfuric acid
<em>Moles Alum:</em>
0.08217 moles sulfuric acid * (2mol KAl(SO4)2•12H2O / 4mol H2SO4) =
0.041085 moles KAl(SO4)2•12H2O
<em>Mass Alum -Molar mass: 474.3884 g/mol-</em>
0.041085 moles KAl(SO4)2•12H2O * (474.3884 g/mol) =
<h3>19.5g is the theoretical yield of alum</h3>
C. 23 pairs
There are a total of 46 chromosomes
<u>A solution of NaF is added to a solution that is 0.0144 M in Ba²⁺. When the concentration of F- exceeds </u><u>0.011 m, BaF₂</u><u> will precipitate.</u>
Let's consider the solution of BaF₂.
BaF₂(s) ⇄ Ba²⁺(aq) + 2 F⁻(aq)
We can use the solubility product constant (Ksp) to find the equilibrium concentration of F⁻ when [Ba²⁺] is 0.0144 M.
When [F⁻] exceeds 0.011 M, BaF₂ will precipitate.
A solution of NaF is added to a solution that is 0.0144 M in Ba²⁺. When the concentration of F- exceeds 0.011 M, BaF₂ will precipitate.
What is BaF₂.?
- BaF2 crystallizes in the cubic Fm3m space group and has a fluorite structural makeup.
- Eight comparable F1 atoms and Ba2+ are joined in a cubic shape with the body in the middle. The average Ba-F bond length is 2.72.
- Four comparable Ba2+ atoms are joined with F1 to create a mixture of corner- and edge-sharing FBa4 tetrahedra.
Learn more about BaF2 crystallizes
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