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I am Lyosha [343]
3 years ago
15

What phase of Moon can be ONLY seen at night?

Chemistry
2 answers:
AveGali [126]3 years ago
7 0
The phase is Waning Crescent phase.

eduard3 years ago
6 0
I think new moon but not 100% sure
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PLS HELP CHEM
Bess [88]

Answer:

Use the formula PV=nRT to get the temperature

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2 years ago
A 1.0 M H2S solution has a pH = 3.75 at equilibrium. What is the value of Ka?
MrRa [10]
The answer is 3.16*10-8
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2. research and development

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3 years ago
PLEASE PLEASE HELP!
valentinak56 [21]

Answer: The number of grams of H_2 in 1620 mL is 1.44 g

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = 1620 ml = 1.62 L  (1L=1000ml)

n = number of moles = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =273K

n=\frac{PV}{RT}

n=\frac{1atm\times 16.2L}{0.0821Latm/K mol\times 273K}=0.72moles

Mass of hydrogen =moles\times {\text {Molar mass}}=0.72mol\times 2g/mol=1.44g

The number of grams of H_2 in 1620 mL is 1.44 g

8 0
3 years ago
An ideal gas in a sealed container has an initial volume of 2.80 L. At constant pressure, it is cooled to 18.00 °C, where its
Aleks04 [339]

Answer:

T_1=-91.18\°C

Explanation:

Hello there!

In this case, given the T-V variation, we understand it is possible to apply the Charles' law as shown below:

\frac{T_1}{V_1}= \frac{T_2}{V_2}

Thus, since we are interested in the initial temperature, we can solve for T1, plug in the volumes and use T2 in kelvins:

T_1= \frac{T_2V_1}{V_2}\\\\T_1= \frac{(18.00+273.15)K(1.75L)}{(2.80L)}\\\\T_1=182K-273.15\\\\T_1=-91.18\°C

Best regards!

6 0
3 years ago
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