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3 years ago

Can anyone help me with this?

Chemistry

1 answer:

satela [25.4K]3 years ago

4 0

Answer:liquids and gases

Explanation:

friction

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Answer:a) organic

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When you compress a spring, which type of energy increase

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3 years ago

PLEASE HELP MEEEEEEEEEEEEEEEEEEEEEEE

Genrish500 [490]

Answer:

Liquid

Explanation:

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What is the molarity of a solution that contains 0.400 mol HCl in 9.79 l solution?

Maslowich

Answer:

Option B, 0.0409 M

Explanation:

1) Data:

a) M = ?

b) n = 0.400 mol

V = 9.79 liters

2) Formula:

M = n / V (in liters)

3) Solution:

M = 0.400 mol / 9.79 liter = 0.04086 M

Since each data contain 3 significant digits, the answer must be reported with 3 significant digits. So, the correct answer is 0.0409 M, which is the option B.

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4 years ago

Consider the reaction:

stich3 [128]

Answer:

$\large \boxed{\text{-851.4 kJ/mol}}$

Explanation:

2Al(s) + Fe₂O₃(s) ⟶ Al₂O₃(s) + 2Fe(s); ΔᵣH = ?

The formula for calculating the enthalpy change of a reaction by using the enthalpies of formation of reactants and products is

$\Delta_{\text{r}}H^{\circ} = \sum \Delta_{\text{f}} H^{\circ} (\text{products}) - \sum\Delta_{\text{f}}H^{\circ} (\text{reactants})$

2Al(s) + Fe₂O₃(s) ⟶ Al₂O₃(s) + 2Fe(s)

ΔfH°/kJ·mol⁻¹: 0 -824.3 -1675.7 0

$\begin{array}{rcl}\Delta_{\text{r}}H^{\circ} & = & [1(-1675.7) + 2(0)] - [2(0) - 1(-824.3)]\\& = & -1675.7 + 824.3\\& = & \textbf{-851.4 kJ/mol}\\\end{array}\\\text{The enthalpy change is } \large \boxed{\textbf{-851.4 kJ/mol}}$

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4 years ago