Question

You decide to build a small generator by rotating a coiled wire inside a static magnetic field of 0.38 T. You construct the apparatus by coiling wire into 4 loops of radius 0.20 m. If the coils rotate at 2.0 revolutions per second and are connected to a device with 200Ω resistance, calculate the average power PaveragePaverage supplied to that device.

Answer 1

Answer:

0.0288 W

Explanation:

$/omega=2 rev/s=2*2\pi= 12.56637 rad/s$

Energy, E is given by

$E=NBA\omega$ where N is number of loops, A is area and B is static magnetic field

Substituting 4 for N, 0.38 T for B, and area calculated

$E=4*0.38*(\pi*0.2^{2})*12.56637=2.400288 V$

E=2.4 V

To get the average power

$P_{average}=\frac {E^{2}}{R}$ where R is resistance

$P_{average}=\frac {2.4^{2}}{200}=0.0288 W$