Answer:
The two rays, CY and DM are diverging rays and when extended behind the mirror, they appear to intersect each other at point M'. Therefore, the properties of the images formed here are formed behind the mirror, between the pole and principal focus (f), the images are diminished and are virtual and erect.
Explanation:
<h2>Spherical Mirrors</h2>
- There are two kinds of spherical mirrors, concave and convex.
- The focal point (F) of a concave mirror is the point at which a parallel beam of light is "focussed" after reflection in the mirror. ...
- The focal length (f) and radius of curvature (R) are defined in the diagram at the right.
<h3>hope it helps and thanks for following </h3><h2>please give brainliest </h2>
Answer:
(a)T= M2 × g, (b)T= (M1 + M2)g, (c)T= M2 (a + g) and (d)T=(M1 + M2) (a + g)
Explanation:
M1 is hanged upper and M2 is lower at Rest.
(a) For M2
T2 = Weight of the Body M2= M2 × g
(b) T1 = Weight of the Body M2 + Weight of the Body M2
T1 = M1 g + M2 g = (M1 + M2)g
M1 is hanged upper and M2 is lower at accelerated upwards ( F = T - W)
(c) For M2
⇒T = M2a + M2g = M2 (a + g)
(d) For M1
T = (M1 + M2) a + (M1 + M2) g
⇒ T = (M1 + M2) (a + g)
Answer:
F = 51.3°
Explanation:
The component of weight parallel to the inclined plane must be responsible for the rolling back motion of the car. Hence, the force required to be applied by the child must also be equal to that component of weight:
where,
W = Weight of Wagon = 150 N
θ = Angle of Inclinition = 20°
Therefore,
<u>F = 51.3°</u>
When the balanced force is applied on the ball It will roll away from the force.
<u>Explanation:</u>
- A ball lies on the floor in rest. If the balanced force is applied to
the ball, the force will push away.
- The forces would include gravity and the forces of air particles entering the ball from almost all directions.
- And the ground is exercising the force and shifting away from the impact.
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