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Basile [38]
3 years ago
7

In which graph is acceleration the slope?

Physics
2 answers:
shtirl [24]3 years ago
7 0

Answer:

it may help u I hope leave comment plz

olga2289 [7]3 years ago
4 0

Answer:

<em>Velocity</em><em> </em><em>-</em><em>time</em><em> </em><em>graph</em><em> </em>

Explanation:

hope it helps ✌️✌️

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Several objects were dropped from a balcony. Use the data below to draw conclusions about the results of these drops. Be sure to
levacccp [35]

The answer is wait can u explain iagaing Again*

3 0
3 years ago
A car travels 554 miles south in 10.4 hours . what is the velocity of the car ? show all steps
kirill115 [55]

Answer:

<h3>The answer is 53.27 mi/hr</h3>

Explanation:

To find the velocity covered by the car we use the formula

v =  \frac{d}{t}  \\

where

d is the distance

t is the time

From the question

d = 554 miles

t = 10.4 hrs

We have

d =  \frac{554}{10.4}  \\  = 53.2692307...

We have the final answer as

<h3>53.27 mi/hr</h3>

Hope this helps you

4 0
4 years ago
An atoms valence electrons are those electrons that have the highest energy true or false
bazaltina [42]

Answer:

True

Explanation:

An atom's valance electrons are those electrons that have the highest energy. Atoms tend to be stable and nonreactive if they have the highestvalence electrons. In the periodic table, the number of valence electrons in each element decreases from left to right across each period.

4 0
4 years ago
I need help with question 17
Alexxx [7]
It is b i had that qustion 

6 0
3 years ago
According to coulombs law, what will happen to the force between two charged particles if the magnitude are increased by 6 times
seropon [69]

Answer: The electrostatic force will be the same

Explanation:

According to Coulomb's Law, when two electrically charged bodies come closer, appears a force that attracts or repels them, depending on the sign of the charges of this two bodies or particles.  

In this sense, this law states the following:

"The electrostatic force F_{E} between two point charges q_{1} and q_{2} is proportional to the product of the charges and inversely proportional to the square of the distance d that separates them, and has the direction of the line that joins them"  

 

F_{E}= K\frac{q_{1}.q_{2}}{d^{2}}  (1)

Being K is a proportionality constant.  

Now, if each q_{1} and q_{2} are increased by 6, and the distance between them as well, we will have the following:

F_{E}= K\frac{6 q_{1}. 6 q_{2}}{(6d)^{2}}  (2)

F_{E}= 36 K\frac{q_{1}. q_{2}}{36d^{2}}  (3)

Simplifying:

F_{E}= K\frac{q_{1}.q_{2}}{d^{2}}  (4)

Comparing (1) with (4) we can see the electrostatic force is the same.

4 0
4 years ago
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