Answer:
Places in binary coding
1 - 2 - 4 - 8 - 16 - 32 - 64 - 128 - 256 - 512 - 1024 - 2048
2483 - 2048 = 435 there is 1 in the 2048 position
435 - 256 = 179 there is 1 in the 256 position
179 - 128 = 51 there is 1 in the 128 position
51 - 32 = 19 there is 1 in the 32 position
19 - 16 = 3 there is 1 in the 16 position
3 - 2 = 1 there is 1 in the 2 position
1 - 1 = 0 there is 1 in the 1 position
10011011 0011 would be the binary result
Check:
2048 + 0 + 0 + 256 + 128 + 0 + 32 + 16 + 0 + 0 + 2 + 1 = 2483
Answer:
5.33333.....
Step-by-step explanation:
I used symbolab to get my answer make me brainleist pls
Answer:
Step-by-step explanation:
Formula = a^2 + b^2 = c^2
Putting values
= (31)^2 + (48)^2 = (51)^2
= 961 + 2304 = 2601
= 3265 = 2601
Both sides are not equal so it is not a right triangle
1/2 divided by 1/6 is 3
use KCF strategy
1/2 x 6/1=3
1x6=6
2x1=2
6/2=3
Answer:
6.9
7.-5
8.-10
Step-by-step explanation:
