There is no significance to the other focus. There's not necessarily anything there.
The efficiency<span> of a heat engine can be calculated as the ratio of the work obtained to the heat energy put in at the high temperature,
efficiency = Work_max/T</span>high<span>.
or
efficiency=TH-TL/TH,
where TH is the high temperature and TL is the low temperature.</span><span>
In our case the heat engine operates between 600K and 800K. SO, TH=800K and TL=600K.
The efficiency is: e=800-600/800=200/800=0,25</span>
Answer:
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F = GMm/r^2
So F is proportional to 1/r^2
F2 = 2700 x ( 1 / 3^2 ) = 300N
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