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3 years ago

Suppose you increase your walking speed from 6 m/s to 15m/s in a period of 3 seconds what is your acceleration

1 answer:

7 0

Avg acceleration; under constant acceleration condition only; = Vf-Vi/time
a=Vf-Vi/time=(15m/s-6m/s)/(3s)=
(9m/s)/(3s)=3m/s^2

Hope this helps. Thanks.

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katovenus [111]

Answer:

go to : www.planetresourses.com/test2.00/answers, ant type in that test name

Explanation:

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3 years ago

What effect does an u balanced force have on an object?

Free_Kalibri [48]

Effect of balanced force'
*net force is zero
*no change in shape
*no change in size
*equal and opposite force

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4 years ago

Consider a supersonic missile flying at Mach 2.5 at an altitude of 10 km. Assume that the angle of the shock wave from the nose

NNADVOKAT [17]

Answer:

The distance at which nose of the vehicle will the shock wave impinge upon the ground is approximately 23km

Explanation:

Let

u be Mach angle

M be Mach Number = 2.5

h be altitude = 10km

d be distance between nose of the vehicle with which the shock wave impinge upon the ground

Using;

Sin u = 1/M

u = arcSin (1/M)

u = arcSin (1/2.5) = 23.58°

Using angle at a point rule = 90°

90 - 23.58 = 66.42°

Tan A = opp/adj

Tan 66.42° = d/10

2.2911 * 10 = d

d = 22.911km ≈ 23km

6 0

3 years ago

a 645 N person is wearing stiletto shoes. If she lifts her left leg, and rocks back onto the heel under her right leg, the press

fgiga [73]

Answer:

0.96cm

Explanation:

Given parameters:

Weight of person = 645N

Pressure of the heel = 9000000PA

Unknown

Diameter of the circular base = ?

Solution

Pressure is the force per unit area of a body.

Pressure = $\frac{Force}{Area}$

To solve this problem, find the unknown area of the circle;

Pressure x Area = Force

Area = $\frac{Force}{Pressure}$

Area = $\frac{645}{9000000}$ = 7.17 x 10⁻⁵m²

Note: 1Pa = 1Nm⁻²

Now;

Area of a circle = π r²

r = $\frac{d}{2}$

Area = π x $\frac{d^{2} }{4}$

d is the diameter

d² = 4 x Area x (1/π)

d² = 4 x 7.17 x 10⁻⁵ x (1/3.14) = 9.13 x 10⁻⁵

d = 0.0096m

To cm;

100cm = 1m

0.0096m; 0.0096 x 100= 0.96cm

7 0

3 years ago

A High Dive A 62.3 kg person jumps from rest off a 3.11 m-high tower straight down into the water. Neglect air resistance during

yuradex [85]

Answer:

2276.1 N

Explanation:

We are given that

Mass of person,m=62.3 kg

Initial velocity,u=0

Final velocity,v=0

Initial kinetic energy=Final kinetic energy=0

y=3.11 m

d=1.14 m

h=3.11+1.14=4.25 m

Final height, h'=0

Work done=Change in P.E energy

$-Fd=mg(h'-h)=-mg(h-h')$

$Fd=mg(4.25-0)$

$F=\frac{62.3\times 9.8\times 4.25}{1.14}$

$F=2276.1 N$

6 0

3 years ago