Answer: Its A because i had the same question and it was a
Answer:
The specific heat for the metal is 0.466 J/g°C.
Explanation:
Given,
Q = 1120 Joules
mass = 12 grams
T₁ = 100°C
T₂ = 300°C
The specific heat for the metal can be calculated by using the formula
Q = (mass) (ΔT) (Cp)
ΔT = T₂ - T₁ = 300°C - 100°C = 200°C
Substituting values,
1120 = (12)(200)(Cp)
Cp = 0.466 J/g°C.
Therefore, specific heat of the metal is 0.466 J/g°C.
I used to wish that I can fly
Answer:
simple, Volt =change in potential energy/Charge
the unit of energy is newton meter (Force*distance)
the unit of charge is coloumb
So, Volt/meter=newton* meter/coloumb*meter
=newton/coloumb (hence proved)
This unit is the potential drop per unit of length in a conductive wire with uniform resistance
Answer:
416.667 m/s
Explanation:
divide the distance by the time
