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ladessa [460]
3 years ago
14

a 645 N person is wearing stiletto shoes. If she lifts her left leg, and rocks back onto the heel under her right leg, the press

ure the heel exerts on the floor is 9000000 PA. what is the diameter of the circular base of the heel in centimeters?
Physics
1 answer:
fgiga [73]3 years ago
7 0

Answer:

0.96cm

Explanation:

Given parameters:

Weight of person = 645N

Pressure of the heel = 9000000PA

Unknown

Diameter of the circular base = ?

Solution

Pressure is the force per unit area of a body.

  Pressure = \frac{Force}{Area}

To solve this problem, find the unknown area of the circle;

             Pressure x Area = Force

         Area     = \frac{Force}{Pressure}

           Area  = \frac{645}{9000000} = 7.17 x 10⁻⁵m²

Note: 1Pa = 1Nm⁻²

Now;

  Area of a circle = π r²

         r = \frac{d}{2}

    Area =  π x \frac{d^{2} }{4}

d is the diameter

                    d²  = 4 x Area  x (1/π)

                d² = 4 x 7.17 x 10⁻⁵ x  (1/3.14) = 9.13 x 10⁻⁵

              d = 0.0096m

To cm;

                100cm = 1m

   0.0096m; 0.0096 x 100=  0.96cm

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mr Goodwill [35]

Answer:

True

Explanation:

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2 years ago
In an electromagnetics lab, you are studying two coils which have a mutual inductance of M=300 mH. Suppose that the current in t
Firdavs [7]

Answer:

Explanation:

Given that,

The mutual inductance of the two coils is

M = 300mH = 300 × 10^-3 H

M = 0.3 H

Current increase in the coil from 2.8A to 10A

∆I = I_2 - I_1 = 10 - 2.8

∆I = 7.2 A

Within the time 300ms

t = 300ms = 300 × 10^-3

t = 0.3s

Second Coil resistance

R_2 = 0.4 ohms

We want to find the current in the second coil,

The same induced EMF is in both coils, so let find the EMF,

From faradays law

ε = Mdi/dt

ε = M•∆I / ∆t

ε = 0.3 × 7.2 / 0.3

ε = 7.2 Volts

Now, this is the voltage across both coils,

Applying ohms law to the second coil, V=IR

ε = I_2•R_2

0.72 = I_2 • 0.4

I_2 = 0.72 / 0.4

I_2 = 1.8 Amps

The current in the second coil is 1.8A

7 0
3 years ago
A figure skater skates across a rink of length 50 m in 12.1 seconds. a. What is the average speed of the skater? (2 points) b. I
melamori03 [73]
(a) The skater covers a distance of S=50 m in a time of t=12.1 s, so its average speed is the ratio between the distance covered and the time taken:
v= \frac{S}{t}= \frac{50 m}{12.1 s}=4.13 m/s

(b) The initial speed of the skater is
v_i = 4 m/s
while the final speed is
v_f = 5.3 m/s
and the time taken to accelerate to this velocity is t=2 s, so the acceleration of the skater is given by
a= \frac{v_f - v_i}{t}= \frac{5.3 m/s-4.0 m/s}{2.0 s}=0.65 m/s^2

(c) The initial speed of the skater is 
v_i = 13.0 m/s
while the final speed is 
v_f=0
since she comes to a stop. The distance covered is S=8 m, so we can use the following relationship to find the acceleration of the skater:
2aS=v_f^2 -v_i^2
from which we find
a= \frac{-v_i^2}{2S}= \frac{-(13.0m/s)^2}{2 \cdot 8.0 m}=-10.6 m/s^2
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4 0
3 years ago
A cube with 30-cm-long sides is sitting on the bottom of an aquarium in which the water is one meter deep. (Round your answers t
OleMash [197]

Answer:

A) hydrostatic force on top of cube = 882.9N

B) hydrostatic force on sides of cube = 0N

Explanation:

Detailed explanation and calculation is shown in the image below

4 0
3 years ago
A cart is pulled by a force of 250 N at an angle of 35° above the horizontal. The cart accelerates at 1.4 m/s2. The free-body di
Vikki [24]

Answer:

Mass of the cart = 146 kg

Explanation:

A cart is pulled by a force of 250 N at an angle of 35° above the horizontal.

The cart accelerates at 1.4 m/s² horizontally.

Horizontal force = Fcosθ = 250 cos35° = 204.79N

We have F = ma

Substituting

        204.79 = m x 1.4  

              m = 146.28 kg = 146 kg

Mass of the cart = 146 kg

3 0
3 years ago
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