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ladessa [460]
3 years ago
14

a 645 N person is wearing stiletto shoes. If she lifts her left leg, and rocks back onto the heel under her right leg, the press

ure the heel exerts on the floor is 9000000 PA. what is the diameter of the circular base of the heel in centimeters?
Physics
1 answer:
fgiga [73]3 years ago
7 0

Answer:

0.96cm

Explanation:

Given parameters:

Weight of person = 645N

Pressure of the heel = 9000000PA

Unknown

Diameter of the circular base = ?

Solution

Pressure is the force per unit area of a body.

  Pressure = \frac{Force}{Area}

To solve this problem, find the unknown area of the circle;

             Pressure x Area = Force

         Area     = \frac{Force}{Pressure}

           Area  = \frac{645}{9000000} = 7.17 x 10⁻⁵m²

Note: 1Pa = 1Nm⁻²

Now;

  Area of a circle = π r²

         r = \frac{d}{2}

    Area =  π x \frac{d^{2} }{4}

d is the diameter

                    d²  = 4 x Area  x (1/π)

                d² = 4 x 7.17 x 10⁻⁵ x  (1/3.14) = 9.13 x 10⁻⁵

              d = 0.0096m

To cm;

                100cm = 1m

   0.0096m; 0.0096 x 100=  0.96cm

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IRINA_888 [86]

A) 4.7 cm

The formula for the angular spread of the nth-maximum from the central bright fringe for a diffraction from two slits is

sin \theta=\frac{n \lambda}{d}

where

n is the order of the maximum

\lambda is the wavelength

a is the distance between the slits

In this problem,

n = 5

\lambda=525 nm =5.25\cdot 10^{-7} m

a=4.15\cdot 10^{-2} mm=4.15\cdot 10^{-5} m

So we find

\theta=sin^{-1} (\frac{(5)(5.25\cdot 10^{-7} m)}{4.15\cdot 10^{-5} m})=3.62^{\circ}

And given the distance of the screen from the slits,

D=75.0 cm = 0.75 m

The distance of the 5th  bright fringe from the central bright fringe will be given by

y=D tan \theta = (0.75 m)tan 3.62^{\circ}=0.047 m = 4.7 cm

B) 8.1 cm

The formula to find the nth-minimum (dark fringe) in a diffraction pattern from double slit is a bit differente from the previous one:

sin \theta=\frac{(n+\frac{1}{2}) \lambda}{d}

To find the angle corresponding to the 8th dark fringe, we substitute n=8:

\theta=sin^{-1} (\frac{(8+\frac{1}{2})(5.25\cdot 10^{-7} m)}{4.15\cdot 10^{-5} m})=6.17^{\circ}

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y=D tan \theta = (0.75 m)tan 6.17^{\circ}=0.081 m = 8.1 cm

5 0
3 years ago
What is the latitude and longitude of the copper mine in Wisconsin (WI)?
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The answer to your question is A. 
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3 years ago
A 1-kg book is at rest on a desk. Determine the force the desk exerts on the book<br>​
Katena32 [7]
<h3>Answer:</h3>

\displaystyle F_n = 9.8 \ N

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
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  • Left to Right

<u>Physics</u>

<u>Forces</u>

SI Unit: Newtons N

Free Body Diagrams

Gravitational Force: \displaystyle F_g = mg

  • m is mass (in kg)
  • g is Earth's gravity (<em>9.8 m/s²</em>)

Normal Force: \displaystyle F_n

Newton's Law of Motions

  1. Newton's 1st Law of Motion: An object at rest remains at rest and an object in motion stays in motion
  2. Newton's 2nd Law of Motion: F = ma (Force is equal to [constant] mass times acceleration)
  3. Newton's 3rd Law of Motion: For every action, there is an equal and opposite reaction
<h3>Explanation:</h3>

<u>Step 1: Define</u>

1 kg book at <em>rest</em>

<u>Step 2: FBD</u>

<em>See Attachment</em>

<em>Draw a free body diagram to label the forces acting upon the book. We see that we would have gravitational force from Earth pointing downwards and normal force from the surface of the desk pointing upwards.</em>

<em>Since the book is not moving, we know that ∑F = 0 (sum of forces equal to 0).</em>

<u>Step 4: Find Normal Force</u>

  1. Define Forces [Newton's Law of Motions]:                                                 \displaystyle \sum F = 0
  2. [Newton's Law of Motions] Substitute in forces:                                         \displaystyle F_g - F_n = 0
  3. [Newton's Law of Motions] [Addition Property of Equality] Isolate \displaystyle F_n:     \displaystyle F_g = F_n
  4. [Newton's Law of Motions] Substitute in \displaystyle F_g:                                               \displaystyle mg = F_n
  5. [Newton's Law of Motions] Rewrite:                                                             \displaystyle F_n = mg
  6. [Newton's Law of Motions] Substitute in variables:                                   \displaystyle F_n = (1 \ kg)(9.8 \ \frac{m}{s^2})
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3 years ago
A 0.4 kg ball is thrown straight up into the air with a velocity of 12.2 m/s. What maximum height will it reach?
AysviL [449]

Answer:

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Explanation:

We have,

Mass of a ball is 0.4 kg

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It is required to find the maximum height reached by the ball.

Concept used : Law of conservation of energy.

Solution,

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