A) 4.7 cm
The formula for the angular spread of the nth-maximum from the central bright fringe for a diffraction from two slits is

where
n is the order of the maximum
is the wavelength
is the distance between the slits
In this problem,
n = 5


So we find

And given the distance of the screen from the slits,

The distance of the 5th bright fringe from the central bright fringe will be given by

B) 8.1 cm
The formula to find the nth-minimum (dark fringe) in a diffraction pattern from double slit is a bit differente from the previous one:

To find the angle corresponding to the 8th dark fringe, we substitute n=8:

And the distance of the 8th dark fringe from the central bright fringe will be given by

The answer to your question is A.
45N and 91W
<h3>
Answer:</h3>

<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Physics</u>
<u>Forces</u>
SI Unit: Newtons N
Free Body Diagrams
Gravitational Force: 
- m is mass (in kg)
- g is Earth's gravity (<em>9.8 m/s²</em>)
Normal Force: 
Newton's Law of Motions
- Newton's 1st Law of Motion: An object at rest remains at rest and an object in motion stays in motion
- Newton's 2nd Law of Motion: F = ma (Force is equal to [constant] mass times acceleration)
- Newton's 3rd Law of Motion: For every action, there is an equal and opposite reaction
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
1 kg book at <em>rest</em>
<u>Step 2: FBD</u>
<em>See Attachment</em>
<em>Draw a free body diagram to label the forces acting upon the book. We see that we would have gravitational force from Earth pointing downwards and normal force from the surface of the desk pointing upwards.</em>
<em>Since the book is not moving, we know that ∑F = 0 (sum of forces equal to 0).</em>
<u>Step 4: Find Normal Force</u>
- Define Forces [Newton's Law of Motions]:

- [Newton's Law of Motions] Substitute in forces:

- [Newton's Law of Motions] [Addition Property of Equality] Isolate
: 
- [Newton's Law of Motions] Substitute in
: 
- [Newton's Law of Motions] Rewrite:

- [Newton's Law of Motions] Substitute in variables:

- [Newton's Law of Motions] Multiply:

Answer:
Maximum height is 7.59 m.
Explanation:
We have,
Mass of a ball is 0.4 kg
It is thrown straight up into the air with a velocity of 12.2 m/s.
It is required to find the maximum height reached by the ball.
Concept used : Law of conservation of energy.
Solution,
Here, the energy of the ball remains conserved. Let h is the maximum height reached by the ball such that,

So, the maximum height reached by the ball is 7.59 m.