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1 answer:
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1) The distance travelled by the rocket can be found by using the basic relationship between speed (v), time (t) and distance (S):
Rearranging the equation, we can write
In this problem, v=14000 m/s and t=150 s, so the distance travelled by the rocket is
2) We can solve the second part of the problem by using the same formula we used previously. This time, t=300 s, so we have:
Answer:
Period of motion is approximately 0.5447 seconds
Explanation:
We start by calculating the constant "k" of the spring which can be derived from the fact that an object of mass 12 g produced a stretch of 3.4 cm: (we write everything in SI units)
F = k * x
0.012 kg * 9.8 m/s^2 = k 0.034 m
k = 0.012 kg * 9.8 m/s^2 / (0.034 m)
k = 3.46 N/m
now we use the formula for the period (T) of a spring of constant k with a hanging mass 'm':
which in our case becomes: