Question

A High Dive A 62.3 kg person jumps from rest off a 3.11 m-high tower straight down into the water. Neglect air resistance during the descent. She comes to rest 1.14 m under the surface of the water. Determine the magnitude of the average force that the water exerts on the diver. This force is nonconservative.

Answer 1

Answer:

2276.1 N

Explanation:

We are given that

Mass of person,m=62.3  kg

Initial velocity,u=0

Final velocity,v=0

Initial kinetic energy=Final kinetic energy=0

y=3.11 m

d=1.14 m

h=3.11+1.14=4.25 m

Final height, h'=0

Work done=Change in P.E energy

$-Fd=mg(h'-h)=-mg(h-h')$

$Fd=mg(4.25-0)$

$F=\frac{62.3\times 9.8\times 4.25}{1.14}$

$F=2276.1 N$