Let O be the point of intersection of diagonals.
Consider triangles FOE and EOD:
FO = OD, ∠FOE = ∠EOD and OE is a common side ⇒
triangles FOE and EOD are congruent.
In congruent triangles all corresponding sides and are congruent ⇒
EF = DE = 6
Answer:
1) f(g(2)) = 24
2) f(g(-1)) = -4
Step-by-step explanation:
1) GIven f(x) = x²+2x and g(x) = 2x
f(g(x)) = f(2x)
f(2x) = (2x)² + 2(2x)
f(2x) = 4x² + 4x
f(g(x)) = 4x² + 4x
f(g(2)) = 4(2)² + 4(2)
f(g(2)) = 16+8
f(g(2)) = 24
2) f(x) = x+1 and g(x) = 5x
f(g(x)) = f(5x)
f(5x)= 5x + 1
f(g(x)) = 5x + 1
f(g(-1)) = 5(-1) + 1
f(g(-1)) = -5+1
f(g(-1)) = -4
Answer:
A = 58
B =:25
Step-by-step explanation:
C = A + B
83 = 9x + 4 + 4x + 1
83 = 13x + 5
13x = 78
x = 78/13
x = 6
A = 9x + 4 = 9 x 6 + 4 = 58
B = 4x + 1 = 4 x 6 + 1 = 25
Answer : 3.4
Explanation: 12.6 x 15.2= 191.52
651.168 / 191.52 = 3.4
