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Irina18 [472]
4 years ago
11

What is a good estimate for 380% of 60

Mathematics
2 answers:
lana [24]4 years ago
5 0
I would multiply 60 by 3, since its 300+%

60 x 3 = 180 

From there I would then add at least half of 60, which is 30

180 + 30 = 210

Since it is 380, I would just add another 20 to the equation to get around :

210 + 20 = 230

This should be a good enough estimate that is close to 380% of 60 <span />
Damm [24]4 years ago
4 0
I would personally write it as a proportion:

x/60=380/100

100x=22800
22800 divided by 100=228

380% of 60 is 228
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Step-by-step explanation:

(950-700)/700

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nirvana33 [79]

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Read 2 more answers
Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

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Step-by-step explanation:

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Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

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y = arctan(t(lnt - 1) + C)

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(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

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Integrate both sides

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2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

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Sholpan [36]
2X^3-2x-40=0
Hope this helps
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