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4 years ago

Answer right you get brainiest also 20 points just number 1 and 2

Mathematics

2 answers:

Klio2033 [76]4 years ago

4 0

Answer:

1. Newton's law of gravitation. Newton's law of gravitation, statement that any particle of matter in the universe attracts any other with a force varying directly as the product of the masses and inversely as the square of the distance between them.

2. The key difference is that Newtonian gravity has a privileged separation of spacetime into space and time, whereas Einsteinian gravity just has spacetime. Edit: to be absolutely clear, Newtonian gravity can be written as spacetime curvature! This is counter to the common statements about the novel thing in GR.

Step-by-step explanation:

viva [34]4 years ago

4 0

Answer:

Step-by-step explanation:

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Not sure how to solve this :/

Sliva [168]

Answer:

SAME

Step-by-step explanation:

5 0

3 years ago

SOMEONE PLEASE HELP ME WITH THIS!! ILL GIVE BRAINLIEST

mel-nik [20]

Answer:

d I think I could be wrong but hey who knows

7 0

2 years ago

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the strip of wood 78 inches long has to be cut into pieces of 3 3/4 inches long how many pieces can be cut

Nataly_w [17]

78 / 3 3/4 =

78/1 / 15/4 =

78/1 x 4 /15 = 312/15 = 20.8

20 pieces 3 3/4 inches long can be cut

6 0

4 years ago

I cant do my mymaths honework ..

sergeinik [125]

Here is the answer for ur question.....

3 0

3 years ago

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The useful life of a certain piece of equipment is determined by the following formula: u=(8d)/h^2, where u is the useful life o

Anni [7]

Answer:

The correct answer is E.

Step-by-step explanation:

First I look for the relationships between the coefficients. The first term corresponds to the base value.

$\frac{8*d}{h^{2}} = \frac{8}{1} * \frac{d}{h^{2} }$

The second term corresponds to the value obtained when the density of the underlying material is doubled and the daily usage of the equipment is halved.

$\frac{2*8*d}{(0,5*h)^{2}} = \frac{16*d}{0,25 * h^{2}} = \frac{16}{0,25} * \frac{d}{h^{2} }$

With the I get the ratio of coefficients of $\frac{d}{h^{2}}$ :

$\frac{8}{1}$ = 8

$\frac{16}{0,25}$ = 64

Now I calculate the percentage increase in the useful life of the equipment as:

% = $\frac{64}{8}$ * %100 = %800

3 0

4 years ago