Answer: You throw an object upwards from the ground with a velocity of 20m/s and it is subject to a downward
acceleration of 9.8 m/s2. How high does it go?
Given Formula Set up Solution
vi=20 m/s
vf=0 m/s
a=-9.8 m/s2
x=?
vf
2 = vi
2 + 2a x (0 m/s)2= (20 m/s)2 + 2 (-
9.8 m/s2) x
x=20.4 meters
Explanation: i known/ i hoped that helped.
Answer: find the attached figure for a and b
Explanation:
A) The second figure depict electric field lines and equipotential lines for two equal but opposite charges. The equipotential lines can be drawn by making them perpendicular to the electric field lines. The potential is greatest (most positive) near the positive charge and least (most negative) near the negative charge.
B) The figure attached depicts an isolated point charge Q with its electric field lines in blue and equipotential lines in green. The potential is the same along each equipotential line, meaning that no work is required to move a charge anywhere along one of those lines. Work is needed to move a charge from one equipotential line to another. Equipotential lines are perpendicular to electric field lines in every case.
Please find the attached file for the figure
So base on your question about the moving air and its is cycled in order to reach equilibrium the answer of the questions are the following
A. what are the two major characteristic that change when air is heated and cooled?
-temperature and molecular structure/ phase of the matter
<span>B. how does these characteristics change the movement of air?
</span>-if the air has lower temp the possibility that it will become heavier than with the higher
<span>C. what is the name of the cycle that develop during these changes? Air cycle</span>
<span>D. why do the changes you describe in part B provide an example of a cycle? because of its molecular activity will increase</span>
Could you supply u with some answer choices please?