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Nadya [2.5K]
4 years ago
5

A student sets up an experiment to determine the inertial mass of a cart. The student has access to the following measurement eq

uipment: a spring scale, a meterstick, and a stopwatch. The student uses the spring scale to pull the cart starting from rest along a horizontal surface such that the reading on the spring scale is always constant. All frictional forces are negligible. In addition to the spring-scale reading, which two of the following quantities could the student measure with the available equipment and then use to determine the inertial mass of the cart? Select two answers.
a. The total distance traveled by the cart after it has been in motion.
b. The average speed of the cart while in motion.
c. The acceleration of the cart while in motion.
d. The time during which the cart is in motion
Physics
2 answers:
wlad13 [49]4 years ago
7 0

Answer:

The correct answers are a and d

Explanation:

In this experiment it can be analyzed using Newton's second law

       F = m a

       m = F / m

The outside is supplied by the spring balance and is constant, therefore the acceleration of the system is also constant.

The acceleration can be found with the kinematic equations

      x = v t + ½ a t²

As we start from rest the initial speed is zero

      a = 2 x / t²

Therefore we need the reading of position and time.

Finally, the relationship between the balance reading and this acceleration of the mass of the system

Let's analyze the answers

a) True. It is one of the necessary quantities

b) False. With the equipment we cannot measure the speed directly

c) false. Acceleration is calculated

d) true. It is the other magnitude necessary for the calculation.

The correct answers are a and d

Dmitriy789 [7]4 years ago
7 0

Answer:

The total distance traveled by the cart after it has been in motion

The time during which the cart is in motion

Explanation:

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Answer:

Publishing results of research projects in peer-reviewed journals enables the scientific and medical community to evaluate the findings themselves. It also provides instructions so that other researchers can repeat the experiment or build on it to verify and confirm the results.

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4 years ago
Two identical loudspeakers that are 5.00 m apart and face toward each other are driven in phase by the same oscillator at a freq
Lunna [17]

Answer:0.0982 m

Explanation:

Given

distance between two loudspeaker is 5 m

frequency (f )=875 Hz

speed of sound (v)=344 m/s

Let x_0 be the smallest distance moved by observer then

Position of observer w.r.t to first speaker is

x_1=\frac{L}{2}-x_0

Position of observer w.r.t to second speaker is

x_2=\frac{L}{2}+x_0

\Delta x=2x_0

For Destructive interference

\Delta x=\left (  m+\frac{1}{2}\right )\cdot lambda

For minimum m=0

and \lambda =\frac{v}{f}

2x_0=\frac{v}{2f}

x_0=\frac{v}{4f}=\frac{344}{4\times 875}=0.0983 m

8 0
3 years ago
A traveling electromagnetic wave in a vacuum has an electric field amplitude of 50.9 V/m. Calculate the intensity ???? of this w
Sliva [168]

Answer:

3.44 W/m²

1.134 J

Explanation:

E₀ = Intensity of electric field = 50.9 V/m

I = Intensity of electromagnetic wave

Intensity of electromagnetic wave is given as

I = (0.5) ε₀ E₀² c

I = (0.5) (8.85 x 10⁻¹²) (50.9)² (3 x 10⁸)

I = 3.44 W/m²

A = Area = 0.0277 m²

t = time interval = 11.9 s

Amount of energy is given as

U = I A t

U = (3.44) (0.0277) (11.9)

U = 1.134 J

5 0
3 years ago
An electron moving in the direction of the +x-axis enters a region where both an electric and magnetic field are applied. The el
labwork [276]

Answer:

The electric field is entering the sheet

Explanation:

When the electron enters the region with the two fields, each one feels a force, so that the direction of the electron is altered, the sum of these two forces is zero.

Let's look for the direction of the magnetic force, for a positive charge, using the rule of the right hand, where the thumb goes in the direction of the velocity of the particle, the fingers extended in the direction of the magnetic field and the palm is in the direction of the strength

Let us apply this rule our case, the thumb goes the x axis and the fingers on the Y axis, therefore, the force is coming out of the sheet, if the load were positive, but with negative the magnetic outside is entering the leaf

The electric force is F = q.E.

For the resultant to be zero the electric force must leave the sheet and as our charge is negative The electric field is entering the sheet

3 0
4 years ago
Electricity from the local power company costs 5.79 cents/kWh. How much would it cost to run a 120-W stereo system for 4.0 hours
xenn [34]

Answer:

<em>Answer: B. $0.78.</em>

Explanation:

<u>Cost of Electricity </u>

The rate of the cost of electricity is usually expressed in $/kWh or cents/kWh because the consumption of electricity is measured in Kilowatts-hour.

The local power company charges 5.79 cents/kWh.

We are required to calculate the cost to run a 120 W stereo system for 4 hours per day for 4 weeks.

The total consumption time is 4 hours/day * 7 days/week *4 weeks = 112 hours

The total energy consumed is 120 W * 112 h =13,440 Wh.

Converting to kWh: 13,440 Wh/1,000 = 13.440 kWh.

Finally, we multiply by the cost rate: 5.79 cents/kWh * 13.440 kWh = 77.8 cents/100 = $0.78.

Answer: B. $0.78.

3 0
3 years ago
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