U = 0.5k(x^2)
1.5 J = 0.5k(0.04m^2)
k = 1875 N/m
Check my math i might be wrong
Answer:
6957.04N
Explanation:
Using
vf2=vi2+2ad
But vf = 0 .
So convert 50km/hr to m/s, and you need to convert 61 cmto m
(50km/hr)*(1hr/3600s)*(1000m/km) = 13.9m/s
61cm * (1m/100cm) = .61m
So n
0 = (13.9m/s)^2 + 2a(.61m)
a = 158.11m/s^2
So
using F = ma
F = 44kg(158.11m/s^2) = 6957.04N
Answer:
187.38 m
Explanation:
Using the equation of motion
s = ut + 1/2gt²...................... Equation 1
Where s = distance of fall, u = initial velocity of the rock, t = time taken for the rock to fall from rest, g = acceleration due to gravity of venus.
Given: u = 0 m/s ( from rest), t = 6.5 s, g = 8.87 m/s².
substituting into equation 1
s = 0(6.5) + 1/2(8.87)(6.5)²
s = 0 + 374.7575/2
s = 187.38 m.
Hence the rock will fall 187.38 m
Answer:
Explanation:
- given S = distance from the first = 3.20cm = 0.032m, t = 1.30×10−8 s
- acceleration = 0.032 X 2 /(1.30×10−8)^2
a = 3.79 x 10^14m/s^2
E = ma /q = 9.11 x 10^-31 x 3.79 x 10^14 / 1.6 x 10^-19
E = magnitude of this electric field. = 2156.3N/C
b) Find the speed of the electron when it strikes the second plate ; V^2 = 2as
= 2 X 3.79 x 10^14 X 0.032
= 4.92 X 10^6m/s