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Greeley [361]
3 years ago
11

A 13.4-mH inductor carries a current i =

{max}" align="absmiddle" class="latex-formula"> sin ωt, with I_{max} = 4.80 A and f = ω/2π = 60.0Hz. What is the self-induced emf as a function of time? (Express your answer in terms of t where e m f is in volts and t is in seconds. Do not include units in your expression.)

Physics
1 answer:
Digiron [165]3 years ago
6 0

The voltage across an inductor ' L ' is

V = L · dI/dt .

I(t) = I(max) sin(ωt)

dI/dt = I(max) ω cos(ωt)

V = L · ω · I(max) cos(ωt)

L = 1.34 x 10⁻² H

ω = 2π · 60 = 377 /sec

I(max) = 4.80 A

V = L · ω · I(max) cos(ωt)

V = (1.34 x 10⁻² H) · (377 / sec) · (4.8 A) · cos(377 t)

<em>V = 24.25 cos(377 t)</em>

V is an AC voltage with peak value of 24.25 volts and frequency = 60 Hz.

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U = 0.5k(x^2)
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What is the minimum speed necessary to make it safely??
spayn [35]

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10-15mph

Explanation:

5 0
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A car traveling at 50 km/h hits a bridge abutment. A passenger in the car moves forward a distance of 61 cm (with respect to the
Karolina [17]

Answer:

6957.04N

Explanation:

Using

vf2=vi2+2ad

But vf = 0 .

So convert 50km/hr to m/s, and you need to convert 61 cmto m

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So n

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3 0
3 years ago
Read 2 more answers
On Venus, the acceleration due to gravity is 8.87 m / s 2 . How far would a 17 g rock fall from rest in 6.5 s if the only force
algol [13]

Answer:

187.38 m

Explanation:

Using the equation of motion

s = ut + 1/2gt²...................... Equation 1

Where s = distance of fall, u = initial velocity of the rock, t = time taken for the rock to fall from rest, g = acceleration due to gravity of venus.

Given: u = 0 m/s ( from rest), t = 6.5 s, g = 8.87 m/s².

substituting into equation 1

s = 0(6.5) + 1/2(8.87)(6.5)²

s = 0 + 374.7575/2

s = 187.38 m.

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7 0
3 years ago
A uniform electric field exists in the region between two oppositely charged plane-parallel plates. An electron is released from
Zigmanuir [339]

Answer:

Explanation:

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  • q = 1.6 x 10_19C
  • using S = at^2/2
  • acceleration = 0.032 X 2 /(1.30×10−8)^2

a = 3.79 x 10^14m/s^2

  • From F = ma
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E = ma /q = 9.11 x 10^-31 x 3.79 x 10^14 / 1.6 x 10^-19

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b) Find the speed of the electron when it strikes the second plate ; V^2 = 2as

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5 0
2 years ago
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